How to add new elements in a big array
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Mina Mansour
on 31 Jul 2019
Commented: Mina Mansour
on 31 Jul 2019
I want to repeat this procedure for NT = 1e4 trials, storing the N-value for each trial in a 1e4 element array, and report the median number. how to make every iteration's length of the group gets added to the N array that I created the zeros syntax? I want just one array of NT elements at the end.
N = zeros(1,NT);
for j = 1:NT
% while loop for recycling the match of birthdays in the same week.
matchFound = 0;
k = 0; group = ceil(365*rand);
while matchFound == 0 && k <= NT
k = k + 1;
newBD = ceil(365*rand);
% if conditioning a group with birthdays in the same week.
if abs(newBD - group(k)) < 7 ...
|| abs(newBD - group(k) - 365) < 7 ...
|| abs(newBD - group(k) + 365) < 7
matchFound = 1;
fprintf('The required number of people is %i\n', length(group))
N = length(group);
end
% New Birthday groups upon each new addition of a person.
newG = [group; newBD];
group = newG;
end
end
fprintf('Median Number of People %i ', median(N))
end
0 Comments
Accepted Answer
James Tursa
on 31 Jul 2019
Maybe assign into elements of N with indexing:
N(j) = length(group);
3 Comments
James Tursa
on 31 Jul 2019
I would assume the same place you are assigning it now. Just change the left hand side from N to N(j).
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