## How to assign vectors to existing vector

### karishma koshy (view profile)

on 7 Aug 2019
Latest activity Edited by madhan ravi

on 15 Sep 2019
Hi all
I want to assign a set of vectors in place of zero to existing vectors (ventor_2). But I always want to check the the new set of vectors (newvector_2) does not have the number that exist in previous vector (vector_1)
Vector_1 = [ 1 2 3 4]
Vector_2 = [ 2 0 4 0 6 7 ] Newvector_2 = [ 2 5 4 8 6 7]
How can I do that
Thank you

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Be Matlabi

### Be Matlabi (view profile)

on 7 Aug 2019
"new set of vectors (newvector_2) does not have the number that exist in previous vector (vector_1)"
--> is there any order in which the non repeated numbers must occur or should it be totally random?
karishma koshy

### karishma koshy (view profile)

on 7 Aug 2019
Yes, it should be in the chronological order
karishma koshy

### karishma koshy (view profile)

on 7 Aug 2019
@Guillaume I have got a set vectors vector_1 before vector_2. So I want to confirm that newly assigned numbers to newvector_2 are not present in vector_1. I know how to check for a single number . But how can I do it for all the numbers in the vector?

### Samatha Aleti (view profile)

on 12 Aug 2019

Without logically going to each element you can use functions like find(), intersect(), setxor() for vectorization in achieving what you need. Here is how you can do it:
vector_1 = [ 1 2 3 4];
vector_2 = [ 2 0 4 0 6 7];
% x is the vector whose elements are to be added to vector_2
x = [1 2 5 8];
xcommon = intersect(x, vector_1);
vector_3 = setxor(x,xcommon);
idxZero = find(~ vector_2);
vector_3(length(idxZero)+1:length(vector_3)) = [];
vector_2(idxZero) = vector_3;
For detailed information on above functions, refer the following document links:

on 12 Aug 2019
Where did x come from?
Samatha Aleti

### Samatha Aleti (view profile)

on 12 Aug 2019
I took "x" as an example here. In your case "x" is the vector set whose elements are to be added in place of zeros of vector_2.

on 12 Aug 2019

on 15 Sep 2019

newvector_2=vector_2;
ix=nnz(~vector_2);
v12=[vector_1,nonzeros(vector_2).'];
u=unique(v12);
d=setdiff(1:max(v12),v12);
newvector_2(~vector_2)=[d,max(v12)+(1:ix-numel(d))]

### Andrei Bobrov (view profile)

on 12 Aug 2019

Let X - interval for input data in 'vector_2'
X = [0, 15];
x = setdiff(X(1):X(2),vector_1); % input data
newvector_2 = vector_2;
lo = vector_2 == 0;
n = sum(lo);
b = repmat(x,1,ceil(n/numel(x)));
newvector_2(lo) = b(randperm(numel(b),n));