How to compare two vector with different dimension
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Hello, I have two vectors
x1 = [1;2;4;7;8];
y1 = [2;5;8;6;1];
which are coordinates of all zero and non zero values of a matrix. And then
x2=[2;8;7]
y2=[6;1;2]
are the coordinates of just the non-zero values. Then how to get the coordinates of zero values? Please help.
5 Comments
Geoff Hayes
on 29 Aug 2019
Boni_PI - so if a coordinate is in (x2,y2) and in (x1,y1) then it is the coordinate of a non-zero value and so should be ignored. If the coordinate is in (x1,y1) and not in (x2,y2) then it is the coordinate of a zero value which you are interested in. Is that correct?
Star Strider
on 29 Aug 2019
Something about this does not make sense. The matrix must be at least (8x8), so assuming it is just that, this:
Ln = sub2ind([8 8], x2, y2);
A = NaN(8);
A(Ln) = 42
Lz = sub2ind([8 8], x1, y1);
A(Lz) = 0
produces:
A =
NaN 0 NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN 0 42 NaN NaN
NaN NaN NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN NaN NaN NaN 0
NaN NaN NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN NaN NaN NaN NaN
NaN 42 NaN NaN NaN 0 NaN NaN
0 NaN NaN NaN NaN NaN NaN NaN
Boni_Pl
on 29 Aug 2019
the cyclist
on 29 Aug 2019
Boni_PI, I edited your question just a bit, using the CODE button to format your vectors.
Adam
on 29 Aug 2019
What are the other options than 'zero or non-zero' in your matrix?! surely that set should cover every element of the matrix?
Answers (1)
Jos (10584)
on 29 Aug 2019
I assume the elements of x and y are linked? Why is the first element of (x2,y2) than not in the list of coordinaties (x1,y1)? I assume this is a mistake.
If I were you, I would link the coordinates explicitly, as rows of a N-by-2 array, allowing to use SETDIFF:
xy_all = [x1(:) y1(:)]
xy_nonzero = [x2(:) y2(:)]
xy_zero = setdiff(xy_nonzero, xy_all, 'rows')
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