How to compare two vector with different dimension

Hello, I have two vectors
x1 = [1;2;4;7;8];
y1 = [2;5;8;6;1];
which are coordinates of all zero and non zero values of a matrix. And then
x2=[2;8;7]
y2=[6;1;2]
are the coordinates of just the non-zero values. Then how to get the coordinates of zero values? Please help.

5 Comments

Boni_PI - so if a coordinate is in (x2,y2) and in (x1,y1) then it is the coordinate of a non-zero value and so should be ignored. If the coordinate is in (x1,y1) and not in (x2,y2) then it is the coordinate of a zero value which you are interested in. Is that correct?
Something about this does not make sense. The matrix must be at least (8x8), so assuming it is just that, this:
Ln = sub2ind([8 8], x2, y2);
A = NaN(8);
A(Ln) = 42
Lz = sub2ind([8 8], x1, y1);
A(Lz) = 0
produces:
A =
NaN 0 NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN 0 42 NaN NaN
NaN NaN NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN NaN NaN NaN 0
NaN NaN NaN NaN NaN NaN NaN NaN
NaN NaN NaN NaN NaN NaN NaN NaN
NaN 42 NaN NaN NaN 0 NaN NaN
0 NaN NaN NaN NaN NaN NaN NaN
Geoff Hayes yes your concept is correct. But How to write the code to separate zero and non zero coordinates from x1 & y1 if the dimension is 50x1. and x2 & y2 vector's dimension is 29x1.
Boni_PI, I edited your question just a bit, using the CODE button to format your vectors.
What are the other options than 'zero or non-zero' in your matrix?! surely that set should cover every element of the matrix?

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Answers (1)

I assume the elements of x and y are linked? Why is the first element of (x2,y2) than not in the list of coordinaties (x1,y1)? I assume this is a mistake.
If I were you, I would link the coordinates explicitly, as rows of a N-by-2 array, allowing to use SETDIFF:
xy_all = [x1(:) y1(:)]
xy_nonzero = [x2(:) y2(:)]
xy_zero = setdiff(xy_nonzero, xy_all, 'rows')

Asked:

on 29 Aug 2019

Answered:

on 29 Aug 2019

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