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How to calculate averaged values from 5-min interval values

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Hello guys.
I have the following question : I have observations for temperature in 5-minute interval, from 1/1/2015 to 31/1/2015 (8928 rows in total). From these data I must extract the hourly average value for temperature, which means that eventually I must have 24 hourly averaged values.
I would appreciate any ideas on the matter!
PS. I have attached the excel file I'm working on. Please note that the format of time appears diferently on Matlab.

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Accepted Answer

David K.
David K. on 19 Sep 2019
Edited: David K. on 25 Sep 2019
Using for loops is a very straightforward way that this can be done:
x = yourData; %your data
size1 = length(x)/12;
size2 = 24;
sub1 = ones(size1,1); % intermediate matrix for averaging every hour
for n = 1:size1 % 8928/12 = 744
sub1(n) = mean(x(12*(n-1)+1 : (12*n))); % averages every 12 values to average every hour
end
hourlyVals = ones(size2 , 1); % 744/31 = 24
for n = 1:size2
hourlyVals(n) = mean(sub1(n:24:size1)); % calculate average of each hour across every day.
end
*edited to fix issue brought up in comments*

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Daphne PARLIARI
Daphne PARLIARI on 1 Oct 2019
Thank you, I tried the correction you proposed but the hourly values of temperature display a completely reverse behavior than normal. I attach plotTcorr.tif: maximum T is during night which is completely irrational.
Before the correction of the code, shape of diurnal T was normal but the values were too low. Now the values seem more normal but the shape of the curve is reversed!
Plus if I use:
size2 = 24;
size3=length(RH);
hourlyValsRH = ones(size2 , 1);
for n = 1:size2
hourlyValsRH(n) = mean(RH(n:24:size3)); % calculate average of each hour across every day.
end
the hourlyValsRH table is missing the value at 13.00...
David K.
David K. on 1 Oct 2019
So I looked at the excel table itself to calculate the mean and it had the same flipped situation. Since it appears that if we only look at the first few days it is as expected then I think it is possible there is something wrong with the data. Your data stops at the 11th hour instead of the full 24 for the last day. perhaps at some point the data got off. I do not know how you would figure it out but I think that is up to you with your data.
To fix the RH I would do the same thing as last time where you just find the places it is missing and fix it manually.
Daphne PARLIARI
Daphne PARLIARI on 2 Oct 2019
If I delete the last 12 values in order to have all the days with 24 hourly values, then the shape of the diurnal variation of T is correct but the values are too low.
If I add again the last 12 values, the curve loses its shape but the hourly values are correct. It seems that I can't have it both ways.

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More Answers (1)

Andrei Bobrov
Andrei Bobrov on 1 Oct 2019
Edited: Andrei Bobrov on 1 Oct 2019
T = readtable('parko_hourly_1_1_2015_eos_16_5_2015_T_RH MINE.xlsx','sheet','Φύλλο1');
T = T(~isnan(T.minute),[1:5,7:8]);
T.YEAR = str2double(T.YEAR);
T{:,{'AIR_TEMP_DegC','RH'}} = str2double(T{:,6:7});
T = T(:,[1:5,8:9]);
T_hour = varfun(@(x)mean(x,'omitnan'),T,'InputVariables',{'AIR_TEMP_DegC','RH'},'GroupingVariables','HOUR');

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Daphne PARLIARI
Daphne PARLIARI on 31 Oct 2019
Dear Andrei, I would like to ask a further question on your code which has worked dreamily.
Is there a way to create an intermediate matrix (before extracting the 24 hourly values of T) which will contain one hourly value of temperature for every hour of each day? With this, I need to have a temperature at 00.00 on 1/1/2015, temperature at 01.00 on 1/1/2015 and so on until 23.00 on 31/5/2015.
Is this applicable?

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