# Problem of finding lag when using xcorr

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Hi everyone,

Thank ou for your watching! I have some problem in using xcorr. Basically I have two groups of data, group1 follows the function sin(x) and group2 follows the function sin(x+3/50). The x region is from 0 to 2 and sampling frequency is 100 (201 dots in total). I can see the lags clearly through the function equation and the plot out, but when I try to use the xcorr to find the lags, the maximum always occurs at the center of the output matrix, which means the lag equals to zero. Is there anyway to solve this problem?

I find someone who has the same problem with me, but his data is a group of data close to a mean value, the method mentions in that page doesn'r work in my case.

Here is the link for his problem:https://www.mathworks.com/matlabcentral/answers/431015-cross-correlation-of-two-signal-always-shows-unexpected-0-lag

Thanks for your reading and wish you have a nice day!

Best,

Zhikun

##### 0 Comments

### Answers (3)

Daniel M
on 12 Nov 2019

Yes, running this gives a max lag at 0. That is indicating that y matches x the best in their current positions. Shifting y by any value will make it agree less. You're expecting to see a lag of 3/50 = 0.06 right? (This is equal to 6 samples).

clearvars

clc

close all

fs = 100;

t = 0:1/fs:2;

x = sin(t);

y = sin(t + 3/50);

[r1,lagsy] = xcorr(x,y);

[mr1,locmaxy] = max(r1);

lagsy(locmaxy)/fs

% ans = 0

y2 = circshift(y,6); % shift it by 6 samples

[r2,lagsy2] = xcorr(x,y2);

[mr2,locmaxy2] = max(r2);

lagsy2(locmaxy2)/fs

% ans = 0

% Plot the results

figure

plot(t,x,t,y,t,y2,'k--')

legend('x','y','y2','location','southeast')

Notice that mr1 > mr2. Look at the plot of y2. It's easy to see that any shift of y would lead to less correlation with x than the original signal.

HOWEVER, if you allow the oscillations to go through one full period, then yes, you get the correct value of 0.06.

clearvars

clc

close all

fs = 100;

t = 0:1/fs:2*pi;

x = sin(t);

y = sin(t + 3/50);

[r1,lagsy] = xcorr(x,y);

[mr1,locmaxy] = max(r1);

lagsy(locmaxy)/fs

% ans = 0.06

##### 4 Comments

Daniel M
on 16 Nov 2019

Linas Svilainis
on 2 Dec 2019

Yes, essential problem is that signal is sampled wrong. Majority of signal processing techniques assume periodical signal (especially xcorr). Try to make several copies of your signal fragment and put them next to each other-does your real signal looks like this? Probably not.

1.Try to increase the sampling range.

2. Try using subsample delay estimation:

if you will combine 1 and 2 results should be acceptable

Linas Svilainis
on 5 Dec 2019

Of course, it would be helpfull to increase the record length first, if possible.

##### 0 Comments

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