Creating an array from 1 to n
734 views (last 30 days)
Show older comments
Agnieszka Polak
on 20 Dec 2019
Commented: Hans Henning Erle
on 17 Nov 2021
Hello!
I am trying to create an array of integers from 1 to n [1 2 3 ..... n], where n is a variable that can change.
How should I approach that?
Thank you!
3 Comments
Luis Benitez Prieto
on 27 Jul 2021
It is elemantary but also not. If you look at the accepted answer below. The answer is creating a double array, the numbers inside are integer values, but not of interger format.
I actually was interested in this question because when I want to create an array of integers I do not want to create a double array in the process by doing something like:
uint32([1:10])
Instead, I would like to directly create an integer array. And thats something I have not easily found in the documentation and a legit question in my opinion. Perhaps thats what the poster is asking for.
Stephen23
on 27 Jul 2021
Edited: Stephen23
on 27 Jul 2021
@Luis Benitez Prieto: like this:
V = uint32(1):uint32(10)
class(V)
Note that just one uint32 input is sufficient to define the output as uint32:
class(uint32(1):10)
class(1:uint32(10))
Note that the square brackets in your example are superfluous and misleading:
Accepted Answer
More Answers (0)
See Also
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!