Generate an array within three loops

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melad atunse
melad atunse on 16 Jan 2020
Commented: David Hill on 16 Jan 2020
82158807_848872355563229_1562809247484346368_n.png

Answers (1)

David Hill
David Hill on 16 Jan 2020
count=1;
for n=.1:.1:.5
for m=.1:.1:.5
for k=1:5
c(count)=94*2.4^n*.4^m;%1^k is always 1, so it doesn't matter
count=count+1
end
end
end
  2 Comments
melad atunse
melad atunse on 16 Jan 2020
First, thank you very much for your interest
Secondly I have other data in which the values of A (1,4) are more and less than 1, for example 0.5 or 1.5 then what will I do
David Hill
David Hill on 16 Jan 2020
count=1;
a=[94 2.4 .4 1];
for n=.1:.1:.5
for m=.1:.1:.5
for k=.1:.1:5
c(count)=A(1,1)*A(1,2)^n*A(1,3)^m*A(1,4)^k;
count=count+1
end
end
end

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