Replacing character between square brackets

A={'[ABC; DEF];[GHI; JKH];';  '[ZBC; YEF];[XHI; UKH];'}

I need to replace ";" only which are appearing within sqare brackets with "^"

Answer 1

[Stephen23]

>> A = {'[ABC; DEF];[GHI; JKH];';  '[ZBC; YEF];[XHI; UKH];'}
A = 
    '[ABC; DEF];[GHI; JKH];'
    '[ZBC; YEF];[XHI; UKH];'
>> B = regexprep(A,'(\[[^\]]+);([^\]]+\])','$1^$2')
B = 
    '[ABC^ DEF];[GHI^ JKH];'
    '[ZBC^ YEF];[XHI^ UKH];'

or perhaps:

>> B = regexprep(A,'(?<!\]);(?!\[)','^')
B = 
    '[ABC^ DEF];[GHI^ JKH];'
    '[ZBC^ YEF];[XHI^ UKH];'

[Muhammad Rahil Rafiq]

Thanks Stephen

[Muhammad Rahil Rafiq]

What if we have more than one ";" in a cell

e.g

>> A = {'[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];'; '[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'}

[Stephen23]

"What if we have more than one ";" in a cell"

Then you need to specify the expected output. I cannot guess what you want.

[Muhammad Rahil Rafiq]

My apologies.

Your earlier command is replacing only one last char ";".

I need to replace all ";" within square brackets

[Stephen23]

>> A = {'[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];';  '[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'}
A = 
    '[ABC; DEF; LMN];[GHI; JKH; OPQ; RST];'
    '[ZBC; YEF; UVW; XYY; DFF; TRR];[XHI; UKH];'
>> B = regexprep(A,'(\[[^\]]+\])','${strrep($1,'';'',''^'')}')
B = 
    '[ABC^ DEF^ LMN];[GHI^ JKH^ OPQ^ RST];'
    '[ZBC^ YEF^ UVW^ XYY^ DFF^ TRR];[XHI^ UKH];'

[Muhammad Rahil Rafiq]

Thanks again!