Trying to find the error in logic
1 view (last 30 days)
Show older comments
There is some problem in the logic of this code. It is supposed to segment the lungs from chest radiographs for the set threshold but it is not doing that correctly (providing same results for any threshold value).
clear; clc; close all;
%% Loading images
Threshold = 240;
raw_x_ray='ee.png';
I=imread(raw_x_ray);
figure(101);
imshow(I);
colormap(gray);
title('Grayscale X-Ray');
I=wiener2(I, [7 7]);
figure(102);
subplot(2,1,1);
imshow(I);
subplot(2,1,2);
imhist(I, 256);
a_thresh = I >= Threshold; % set this threshold
[labelImage, numberOfBlobs] = bwlabel(a_thresh);
props = regionprops(a_thresh,'all');
sortedSolidity = sort([props.Solidity], 'descend');
SB = sortedSolidity(1);
if SB == 1
binaryImage = imbinarize(I); figure(103);
imshow(binaryImage); colormap(gray);
SE = strel('square',3);
morphologicalGradient = imsubtract(imdilate(binaryImage, SE),imerode(binaryImage, SE));
mask = imbinarize(morphologicalGradient,0.03);
SE = strel('square',2);
mask = imclose(mask, SE);
mask = imfill(mask,'holes');
mask = bwareafilt(mask,2); % control number of area show
notMask = ~mask;
mask = mask | bwpropfilt(notMask,'Area',[-Inf, 5000 - eps(5000)]);
showMaskAsOverlay(0.5,mask,'r'); % you have to download app/function showMaskAsOverlay
BW2 = imfill(binaryImage,'holes');
new_image = BW2 ;
new_image(~mask) = 0; % invert background and holes
B=bwboundaries(new_image); % can only accept 2 dimensions
figure(104);
imshow(new_image);
ss = strcat('Result_',num2str(Threshold),'.mat');
save(ss,'new_image');
hold on
visboundaries(B);
im8 = im2uint8(new_image);
imwrite(im8, 'ccc.png')
end
2 Comments
John Petersen
on 2 Mar 2020
It would help if you could narrow it down a little more and maybe explain what is wrong about it?
Answers (1)
Daniel Vieira
on 2 Mar 2020
Edited: Daniel Vieira
on 2 Mar 2020
the Threshold parameter doesn't matter at all in your code. you binarize the image with the threshold, measure solidity of blobs, take the largest solidity, and if it's 1 (which is extremely likely) then you throw the previous binarization away and binarize again with default values of imbinarize. I'm not sure that's what you intended to do, but to me it seems unntentional, I don't think this approach goes anywhere.
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!