Solving three simultaneous equations for analytical solution

Hi there,

I am trying to solve for k_t+1, tau_t, l^t-1_2 in terms all other parameters that are taken to be given. You can assume that w(h_t)=exp(bh_t). I have tried executing this code:

syms k2 k1 R B s h a l2 l1 t1 t2 b d

[solk2,solt1,soll2]=solve(k2==(BR(exp(bh)(1-l2-a)-t1)-t2)/(BR+R),t1==(d(exp(bh)(1-l2-a)-k2)-Rk1)/(1+d),l2==(s(exp(bh)(1-a)-k2-t1))/(exp(bh)+sexp(bh)))

I am getting the error message Indexing with parentheses '()' must appear as the last operation of a valid indexing expression.

What should I change in the code to run it properly?

Answer 1

[Stephan]

Keep it short and simple + use "*" for multiplication operations:

syms k2 k1 Rk1 R BR s h a l2 l1 t1 t2 bh d
eq(1) = k2==(BR*(exp(bh)*(1-l2-a)-t1)-t2)/(BR+R);
eq(2) = t1==(d*(exp(bh)*(1-l2-a)-k2)-Rk1)/(1+d);
eq(3) = l2==(s*(exp(bh)*(1-a)-k2-t1))/(exp(bh)+s*exp(bh));
vars = [k2, t1, l2]
[solk2,solt1,soll2]=solve(eq,vars)

Im not sure what you want to do with this code, because the solution for k2, t1 and l2 are already there in the equations.

[Teck Lim]

I was hoping to express k2, t1, and l2 as functions of only parameters. Right now, for example, there is still t1 inside my solution for k2.

[Teck Lim]

I tried the code and it works out fine. Thanks!

Now that I have solved for k2,t1 and l2 in terms of parameters, I want to solve for E and F in the following equation by subbing in the optimal k2, t1, and l2 that I just found on the right hand side.

Does this seem like something that can be coded on MATLAB?

[Stephan]

You might want to use subs.

[Teck Lim]

Alright, thank you