MATLAB Answers

root of nonlinear equation

2 views (last 30 days)
Lidaou Ali
Lidaou Ali on 28 Mar 2020
Commented: Lidaou Ali on 28 Mar 2020
i am working on an electical concepts design problem for a emergency exit door release mechanism. I solved the circuit and found that i(t)=0.25*e^(-t/8c)*cos(t/8c)
i want i(t)=0.1 at t=3 sec
i got the code but it doesnt work
%c= fzero(ft,3);
but i cant get result for c
can someone help me?

Accepted Answer

Torsten on 28 Mar 2020
ft = @( c ) 0.25* ...
instead of
ft = 0.25* ...
Lidaou Ali
Lidaou Ali on 28 Mar 2020
that is correct. i believe i missed an "8"
the right equation is ft=@(c)0.25*exp(-3/(8*c))*cos(3/(8*c))

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!