How to make a 2d structure from 3d structure??

I have a structure(Say A) of size 20 × 18 × 4.

I want to convert it to(Say B) of size 80 × 18

I tried with

B = reshape(A,80,18)

Is this correct?? Please suggest

[Mehmed Saad]

Yup it is correct for arrays and cells

Example

x = rand(20,18,4);
y = reshape(x,80,18);

[Ashish Mishra]

@Muhammad Saad, No, I checked it. The column 2 (val(: , : , 1)) is coming in coulumn 1 from row 21 to row 40. I want to keep my columns intact while concatenating 20× 18 structures four times.

Answer 1

[Mehmed Saad]

x(1,1,1) = 1;
x(1,1,2) = 2;
x(1,2,1) = 3;
x(1,2,2) = 4;
x(2,1,1) = 5;
x(2,1,2) = 6;
x(2,2,1) = 7;
x(2,2,2) = 8;

Now type

x(:)

Output will be

ans =

     1
     5
     3
     7
     2
     6
     4
     8

When you feed data to reshape it converts into this and then reshape to your given dimensions forexample

reshape(x,2,4)
ans =

     1     3     2     4
     5     7     6     8

Inorder to change which data to pick you have to premute the dimensions for example

     x = permute(x,[3 2 1]);
     x(:)
     ans =

     1
     2
     3
     4
     5
     6
     7
     8

Hope this helps

[Tommy]

Ashish,

For your example, I believe this would be

B = reshape(permute(A,[1 3 2]),80,18);