interp1 function error
1 view (last 30 days)
Show older comments
Hello i have made an interpolation of a descrete CSV file which is attached and turned it into continues function using interp1.
it went without an error , but when i tried to plot continues function using xq vector,it said
'Subscript indices must either be real positive integers or logicals.'
Where did i go wrong?
Thanks.
data = load('t2.csv');
x = data(:,1);
y = data(:,2);
%plot(x,y);
%hold on
x_data=x/(1e+6);
y_data=abs(y/(100));
plot(x_data,y_data);
coef_fun = @(lambda) interp1(x_data, y_data(x_data),lambda, 'linear', 'extrap'); %%%%FIRST FUNCTION
xq = linspace(5e-6,13.5e-6,10000);
plot(xq, coef_fun(xq))
%hold off
0 Comments
Accepted Answer
Ameer Hamza
on 8 May 2020
No need to index y_data with x_data
coef_fun = @(lambda) interp1(x_data, y_data, lambda, 'linear', 'extrap'); %%%%FIRST FUNCTION
0 Comments
More Answers (0)
See Also
Categories
Find more on Interpolation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!