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Create row with text from loop for a table

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I want to create a table with a row like this:
[Bar No.1; Bar No.2 ... Bar No.n]
I tried it with:
%N = 4x6;
capa = zeros(size(N,1),1);
i=1;
while i<= size(N,1)
capa(i) = sprintf('Capa #%d',i);
i=i+1;
end
I tried also with fprintf, but it doesn't work.
My table has other information which I want to add this column as first:

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Accepted Answer

Stijn Haenen
Stijn Haenen on 19 May 2020
you can create table headers with:
a=table();
for i=1:10;
a.(sprintf('bar %g',i))=i;
end

  3 Comments

Isai Fernandez
Isai Fernandez on 19 May 2020
Thank you. I get this message: «To assign to or create a variable in a table, the number of rows must match the height of the table.»
I check the size of the matrix which I work and nothing.
Stijn Haenen
Stijn Haenen on 19 May 2020
N=4;
a=table();
for i=1:10;
a.(sprintf('bar %g',i))=zeros(N,1);
end
Isai Fernandez
Isai Fernandez on 19 May 2020
How about adding columns with loops? Can you help me?

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