# How to separate an array into 3

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hjo on 28 May 2020
Commented: Brent Kostich on 29 May 2020
Hi I am trying to divide one array into 3 arrays
let's say A = [11 22 33 44 55 66 77 88 99]
I want to divide A like this:
B = [11 33 55 77]
C = [22 44 66 88]
D = [99]
This is just an example...Could you come up some idea for this?

Stephen Cobeldick on 29 May 2020
>> A = [11,22,33,44,55,66,77,88,99];
>> B = A(1:2:end-1)
B = 11 33 55 77
>> C = A(2:2:end-1)
C = 22 44 66 88
>> D = A(end)
D = 99

Brent Kostich on 28 May 2020
A simple way is by indexing, like so:
A = [11 22 33 44 55 66 77 88 99];
B = A([1, 3, 5, 7]);
C = A([2, 4, 6, 8]);
D = A(9);
If you are looking for a more general solution than explicit indexing, then you will have to provide more parameters for your problem.

hjo on 28 May 2020
Thank you for solution.
But what if A always contains odd number of elements and B and C should take every other elements (explained above) and D is required to take the last element of the array?
for D i figured out the function: lastDigit = A(end);
Could you give me something like this?
Brent Kostich on 29 May 2020
If you wanted to filter by even and odd, then you should have specified that in your question. That operation is not difficult though, see Stephen Cobeldick's answer.