How to separate an array into 3

Hi I am trying to divide one array into 3 arrays

let's say A = [11 22 33 44 55 66 77 88 99]

I want to divide A like this:

B = [11 33 55 77]

C = [22 44 66 88]

D = [99]

This is just an example...Could you come up some idea for this?

Answer 1

[Stephen23]

>> A = [11,22,33,44,55,66,77,88,99];
>> B = A(1:2:end-1)
B =   11   33   55   77
>> C = A(2:2:end-1)
C =   22   44   66   88
>> D = A(end)
D =   99

Answer 2

[Brent Kostich]

A simple way is by indexing, like so:

A = [11 22 33 44 55 66 77 88 99];

B = A([1, 3, 5, 7]);
C = A([2, 4, 6, 8]);
D = A(9);

If you are looking for a more general solution than explicit indexing, then you will have to provide more parameters for your problem.

[gmltn1212]

Thank you for solution.

But what if A always contains odd number of elements and B and C should take every other elements (explained above) and D is required to take the last element of the array?

for D i figured out the function: lastDigit = A(end);

Could you give me something like this?

[Brent Kostich]

If you wanted to filter by even and odd, then you should have specified that in your question. That operation is not difficult though, see Stephen Cobeldick's answer.