# What does "Index exceeds the number of array elements (6)." mean?

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Jonathan Babitsch on 16 Jun 2020
Commented: Jonathan Babitsch on 16 Jun 2020
Hey everybody,
I have a problem concerning my recent work. I get the following error message:
I also attached the code if that helps.
I really have no idea what it is from and why it occures here... What can I do here to avoid the failure?
Thank you a lot in advance!!
Johnny

#### 1 Comment

KSSV on 16 Jun 2020
xlfile is missing......code is huge...
Error is simple, you are trying to extract more number of elemnts then present.
Ex:
A = rand(6,1) ;
A(8)

Mehmed Saad on 16 Jun 2020
Edited: Mehmed Saad on 16 Jun 2020
You are using allepunkte as a for loop iterator. From Line 197 to Line 222 and you basically index two variables namely inside and outside in if else condition. The code syntax is
for allepunkte 1:8
for huellkoerper 1:4
if First_Condition
inside(allepunkte) = true;
else
outside(allepunkte) = true;
end
end
end
Now the problem is you have not initialized the variable inside and outside which means that the maximum index they will get will be their size. So initialize them before for loop starts. This will resolve the index problem

#### 1 Comment

Jonathan Babitsch on 16 Jun 2020
I see this makes perfectly sense! So that means inside+outside is the size of allepunkte? Means in the code I can also put inside{allepunkte}=true and in the same condition outside{allepunkte}=false, then I have a value assigned to every index... This seems to work... Thank you a lot for your help Mehmed, have a nice day!!

Deepak Gupta on 16 Jun 2020
Hello Jonathan,
It's hard to root cause the problem without having the xlsx sheet you are using in your program. But in general this error is thrown when you are trying to access an array index which doesn't exist. At line number 229, you are checking condition, for allepunkte = 1:8, and for that it throws error that index exceeds array size of 6. So program will throw error for any value greater than 6. Try allepunkte = 1:6 at this point and check if you still see error. It's not the solution, it's just a way to root cause the error.
If this doesn't throw error and you have to keep allepunkte = 1:8, then you need to investivate why you are not getting cell arrays of required size.
Hope this helps.

#### 1 Comment

Jonathan Babitsch on 16 Jun 2020
Thank you Deepak!
You described it nicely and it really led me the right way.
Have a nice day and as I said thanks a lot!