compressing a code, help me
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Cauli Vilela Ferreira
on 2 Jul 2020
Answered: Image Analyst
on 2 Jul 2020
Any one knows how to compress this code as much as possible?
for VetorN = fix((20*sqrt(2).^(0:5)))
[row,col] = size(VetorN);
i = (1: col);
discSt.N = VetorN(i);
VN = VetorN;
CD0 = VetorN *3;
if VetorN == 20
CD01 = CD0;
elseif VetorN == 28
CD02 = CD0;
elseif VetorN == 40
CD03 = CD0;
elseif VetorN == 56
CD04 = CD0;
else
CD05 = CD0;
end
pause()
end
MCD0 = [CD01 CD02 CD03 CD04 CD05]
2 Comments
Accepted Answer
madhan ravi
on 2 Jul 2020
VetorN = fix( (20 * sqrt(2) .^ (0 : 5) ) )
MD0 = VetorN * 3;
MD0(end - 1) = [ ]
4 Comments
More Answers (1)
Image Analyst
on 2 Jul 2020
Not sure why it needs to be compressed as much as possible, but this will compress it as much as possible while giving the very same output:
MCD0=[60,84,120,168,339]
This assumes that after that you no longer need the component variables CD01, CD02, CD03, CD04, CD05, and CD06. If you still need those variables for some reason, then of course you'll need to compute them.
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