Dividing in Polar format

How can I divide this using matlab. Answer needs to be in polar format also. Thank you!

[VBBV]

Download this resource from link https://in.mathworks.com/matlabcentral/fileexchange/70244-polar-phasors

[Walter Roberson]

https://www.intmath.com/complex-numbers/4-polar-form.php

[Star Strider]

Meet Patel — See my Answer.

[Meet Patel]

Thanks!

Answer 1

[Star Strider]

This is phasor notation, and derives from the Euler identities.

Divide the numerator magnitude by the denominator magnitude, and subtract the denominator angle from the numerator angle.

EDIT — (23 Sep 2020 at 3:44)

Result1 = 115.47*exp(1j*deg2rad(-30)) / (20*exp(1j*deg2rad(-53.13)))
Result2a = [abs(Result1) rad2deg(angle((Result1)))]
Result2b = [(115.47/20), (-30)-(-53.13)]

producing:

Result1 =
   5.3094 + 2.2679i

Result2a =
    5.7735   23.1300

Result2b =
    5.7735   23.1300

.