append different matrices in a for loop

Hi ,

I have a matrix 3x1024 . And I need to append all data in a for loop 128 times. so want to size of all 384x1024.

Could you help me ?

Thank you !

a = load('x.mat');

b = load('y.mat');

c = load('z.mat');

for i =1:128

% l = (i-1)*3+1;

% m = i*3;

first = a.ss(:,i,:); % a.ss =1024x128

second = b.kk(:,i,:);% b.kk =1024x128

third = c.zz(:,i,:); % c.zz = 1024x128

first = transpose(first); % now size of first = 1x1024

second = transpose(second); % now size of second = 1x1024

third = transpose(third); % now size of third = 1x1024

% all(l:m) = [first;second;third]; % size of all = 3x1024, want size of all to be 384x1024

all = [first;second;third];

end

Answer 1

[Ameer Hamza]

One option is to create a cell array to save data in each iteration and then combine it in the form of a vector at the end. See my answer to this question here: https://www.mathworks.com/matlabcentral/answers/695740-output-of-fun-is-not-a-matrix-the-same-size-as-the-block-in-block-proc#answer_577455

More specifically, something like this

a = load('x.mat'); 
b = load('y.mat');
c = load('z.mat');

C = cell(1,128);
for i =1:128
    %    l = (i-1)*3+1;
    %   m = i*3;
    first  = a.ss(:,i,:);   % a.ss =1024x128
    second = b.kk(:,i,:);% b.kk =1024x128
    third  = c.zz(:,i,:);  % c.zz = 1024x128
    first  = transpose(first); % now size of first = 1x1024
    second = transpose(second); % now size of second = 1x1024
    third  = transpose(third); % now size of third = 1x1024
    % all(l:m) = [first;second;third];  % size of all = 3x1024, want size of all to be 384x1024
    C{i} = [first;second;third]; 
end
all = vertcat(C{:})