Converting sequence to binary based on the value exceeding condition

Say I have a sequence x = [2 4 3 7 5 4 3], and I want to convert the sequence to 1s and 0s based on if the value at each index position is greater than 5. So the output of the function would give y = [0 0 0 1 1 0 0]...what would this function look like?

I have attempted this from the below, could you also explain if this is the correct path?

Many thanks for your help

for i=length(x)

if x(i:end) > 5

y(i) = 1;

else

y(i) = 0;

end

Answer 1

[Image Analyst]

One line of code is all it takes:

y = x > 5

[Image Analyst]

or

y = x >= 5

depending on what you want. (Your question shows it both ways and is ambiguous.)