how to find the sum terms in of binomial expansion
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I need to find the sum of few terms in binomial expansion...more precisely i need to find the sum of this expression:
                   ∑ (nCr) * p^r * q^(n - r)
and limits for summation are from r = 2 to 15. and n=15
any help would be most welcome.
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Accepted Answer
  Ahmed A. Selman
      
 on 11 Apr 2013
        
      Edited: Ahmed A. Selman
      
 on 11 Apr 2013
  
      The general steps to find such a summation are:
- Start a loop over r,
- Calculate each term as a function of (r),
- In the loop, add the terms one by one to a unique matrix,
- After the loop is finished, sum over the added terms.
The code should be something as :
% ∑ (nCr) * p^r * q^(n - r)
clc; clear all
p =...;
q =...;
n = 15;
i = 0;
   for r = 2:15
        i = i+1;
        nCr = ...;% calculate the coefficients here  
        Terms(i) = nCr * p.^r .* q.^(n-r);
   end 
 SumOfTerms = sum(Terms)
The output is in (SumOfTerms), which should be a single value.
I assumed that (nCr) is not a constant, as I expect, it must be a function of (n and r). If it was a constant of (n and r), then define it outside the loop.
I also didn't understand the meaning of ( *| ) at the beginning and end of the formula in your question. If they mean some operation s ( complex conjugate or absolute) then add any of the commands at the very end of the code:
finalSum = conj(SumOfTerms);% for complex conjugate value.
or
finalSum = real(SumOfTerms);% for real value.
and in this case the output will be in (finalSum).
If you tried it and it didn't work, please let me know in which line it made an error, and the error message.
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More Answers (1)
  Roger Stafford
      
      
 on 11 Apr 2013
        With that range of r I would think it would be more efficient to compute
 (q+p)^n-q^n-n*q^(n-1)*p
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