Replacing a cell value in a struct

38 views (last 30 days)
deejt
deejt on 19 Jan 2021
Edited: Image Analyst on 20 Jan 2021
Hello,
I have a struct with 4 fields.
One field contains my conditions (3 conditions, named using strings)
Now I want to replace the strings with numbers. How is that possible? So far I could not find anything :( Is this even possible?
Help is much appreciated!

Accepted Answer

Image Analyst
Image Analyst on 19 Jan 2021
This works:
% Identify what number should replace what character vector.
replacements = {'condi1', 1; 'condi2', 2; 'condi3', 3}
% Make cell array for Conditions
caConditions = {'condi1' 'condi2' 'condi3' 'condi3' 'condi1' 'condi3' 'condi2'}
% Create the whole structure array.
s = struct('subjectnumber', {1 1 1 1 1 1 1}, ...
'condition', caConditions, ...
'rt',{0.12 0.11 0.8 0.9 0.13 0.6 0.12}, ...
'point',{0 40 40 40 20 20 0})
for k = 1 : numel(s)
thisCondition = {s(k).condition}; % Character vector like 'condi1', or 'condi2', etc.
% Compare this condition to the list of them in column 1 of replacements
% and find out which row contains the replacement.
[~, row] = ismember(thisCondition, replacements(:, 1));
% Replace it with the number in column 2
s(k).condition = replacements{row, 2};
end
  2 Comments
deejt
deejt on 19 Jan 2021
Edited: deejt on 19 Jan 2021
Thank you so much! This indeed solved my problem!!!
How would I proceed, if I had so many more entries (because 7 is very easy).
But at this part for example: what if I had 24778 entries - I can't possibly type in everything manually can I?
s = struct('subjectnumber', {1 1 1 1 1 1 1}, ...
'condition', caConditions, ...
'rt',{0.12 0.11 0.8 0.9 0.13 0.6 0.12}, ...
'point',{0 40 40 40 20 20 0})
Image Analyst
Image Analyst on 20 Jan 2021
Edited: Image Analyst on 20 Jan 2021
Are you saying that you could have 25 thousand different strings? If so, rather than a look up table like I used, you'd need to use something like sscanf() to parse/extract the number out of the character string.

Sign in to comment.

More Answers (2)

Image Analyst
Image Analyst on 19 Jan 2021
Yes. For example to set the "condition" field to the number 5, do this:
yourStruct.condition = 5;
It doesn't matter that it used to be a string.
Attach your structure in a .mat file, or give code to create it, if you still have problems.
  4 Comments
Image Analyst
Image Analyst on 19 Jan 2021
AGAIN:
Attach your structure in a .mat file, or give code to create it, if you still have problems.
I need it because I'm not sure how condition is what you showed : 3 character arrays. It can be a character matrix, a string vector, or even a cell array, but I don't know what you have or how you displayed that. Plus answer Bob's questions.
deejt
deejt on 19 Jan 2021
Edited: deejt on 19 Jan 2021
@Image Analyst when I tried your suggestion I received an error msg unfortunately. I attached it here, maybe I am overseeing something! (I am new to programming and just trying to figure out some basics).
"Scalar structure required for this
assignment.
Error in TutorialSession (line 4)
s.condition = 5"

Sign in to comment.


deejt
deejt on 19 Jan 2021
Edited: deejt on 19 Jan 2021
Thank you guys for the effort.
@Bob Thompson Yes, I am trying to do a search/find and replace. In every cell of the field block I want to change the name that is in string to a numerical value.
condi1 should become 1, condi2 should become 2, condi3 should become 3 in every cell these string appear.
Thank you!

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!