For loop help, Matrix manipulation

Hello,

Here is the updated code from a quesion I asked yesterday. I was given a TIFF image, which I imported into Matlab. I then had to find every pixel value greater than 149. My next step was to locate groups of nine points that each had values >149 that were arranged in a 3x3 sub matrix, which I called "kernals". The next step, which I am stuck on, requires me to find the mean of each "kernal", and sort the means into four groups. My attempt is as follows,

imdata = imread('dayonefile.tiff'); % imported array

removed = imdata(1:2048,1:2048); % scale etc. removed

white = removed>149; %values greater than 149 are true, less are false

pixels=imagesc(white,[0 1]); colormap(gray);%colormap image black is less than 150

m=0; for ii=1:2048 for jj=1:2048 if (removed(ii,jj))>149 m=m+1; end end end %total number of pixels with value greater than 149

r=0;%number of "kernals"

t=0;%group one

u=0;%group two

v=0;%group three

w=0;%group four

for ii=2:2047

    for jj=2:2047

        if ((removed(ii-1:ii+1,jj-1:jj+1))>(149))

        r=r+1; %total number of "kernals" (blocks of nine with values greater than 149)   

        if r>0
            Mean(r)=mean2(removed(ii-1:ii+1,jj-1:jj+1));  %Gives the mean of each "Kernal"

            if  ((174)>(Mean(r))>=(150)); %attempt to sort means
            t=t+1;

            elseif ((199)>(Mean(r))>=(175));
            u=u+1;

            elseif ((229)>(Mean(r))>=(200));
            v=v+1;

            else ((255)>(Mean(r))>=(230));
            w=w+1;

            end

           end
        end         

    end
end

This is my first program, and after one day I’m feeling pretty good about it. Once I fix my sorting problem I will be able to submit (as you can imagine I am pretty eager). Thanks in advance for everyone’s help!

Derek

Answer 1

[Sean de Wolski]

if (all(all(removed(ii-1:ii+1,jj-1:jj+1)))>(149)) %added all(all(..P)

if  ((174)>(mean(r)) && mean(r) >=(150)); %two conditions + && required

repeat as necessary for other if statements.