Normalize option in curve fitting toolbox. How does it work?

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Hello everybody,
I would like to regress a curve to the model:
F(t) = k * E(t) + r * E'(t) + u*E''(t) + c
Where the target function F(t) and the input function E(t) are experimental data.
To work with E(t) I fit a sigmoidal function to E(t):
E(t) = b(1) + b(2)./ (1 + exp( -(x - b(3)) ./ b(4)))
Here comes the problem: The fit to E(t) only works, if I set the fitoption 'normalize' to 'on' and the results are very good (r-square > 0.99). But now I want to use the coefficients in b as input to the model for the regression. Because b is from a normalized fit, I receive a different result for the individual terms by using b in the model.
Here is the code to determine b:
[xdata, ydata] = prepareCurveData( x, sig );
expr = @(b(1), b(2), b(3), b(4), x) b(1)+b(2)./(1+exp(-(x-b(3))./b(4)));
ft = fittype(expr, 'independent', 'x', 'dependent', 'y');
opts = fitoptions( ft );
opts.Normalize = 'on';
[fitresult, gof] = fit( xdata, ydata, ft, opts );
In other words: How can I reconstruct E(t) with the coefficients from a normalized E(t) in b?
I hope this is understandable and someone can point me in the right direction. If necessary I can also post the code for the regression on F(t).
Thanks in advance, Kai

Answers (2)

MattH
MattH on 16 Apr 2018
Edited: MattH on 16 Apr 2018
I have a similar question.
From the fitresult "where x is normalized by mean 590.4 and std 151.7" it is possible to get X=(x-590.4)/151.7 and use the coefficients of the regression model(thus answering the question above)
The problem is how to do that programmatically ? It is possible to get the coefficient with coeffvalues(equation) but how can I retrieve mean and std ?
Any idea, anyone ?
Thanks

JOHN GONZALEZ
JOHN GONZALEZ on 16 May 2022
Edited: JOHN GONZALEZ on 16 May 2022
Hello, good afternoon
I had the same problem. I can't take the mean and std of the normalized x from the fit results to make the correct calculations of the regression. Usign the advice of MattH I calculate xmean and xsigma variables appart.

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