How would I write this code using for and while loops/

1 view (last 30 days)
  4 Comments
David Hill
David Hill on 11 Feb 2021
You could use if statement
for i=1:length(V)
if V(i)
V(i)=0;
else
V(i)=1;
end
end
Olivia Gilliam
Olivia Gilliam on 11 Feb 2021
Yeah I finally figured out 2a of the problem. Im working on 2b, so I'm trying to flip every second instance of 0. If I do it right, array V (V = [1, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1]), should become V = [1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1]. I underlined the zeroes that should flip to ones.
This is the code I used:
But, instead of getting V = [1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1]
I get:
Any help?

Sign in to comment.

Answers (1)

Sourabh Kondapaka
Sourabh Kondapaka on 17 Feb 2021
Edited: Sourabh Kondapaka on 18 Feb 2021
I would recommend you to check out the free Matlab OnRamp Course
For 2b:
V = [1, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1];
count = 0;
for i = 1 : length(V)
% Below 'if' condition is same as : if V(i) == 0
if ~V(i)
count = count + 1;
% As you want to modify every second instance, i'm just checking the modulus value of count
% with 2.
if mod(count,2) == 0
V(i) = 1;
end
end
end

Categories

Find more on Cell Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!