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Storing elements to a matrix

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Hi everyone. This my code
clc
clear all
m=[ 1 2 3; 4 5 6; 7 8 9];
c=1;
for k=1:3;
for f= 1:3;
m1(k,f)=(m(c+1,k)+m(c+2,f));
end
end
disp(m1);
for k=1:size(m,2)
M(:,:,k)=m(1,k)+m1;
end
disp(M);
the output of this code is
11 12 13
12 13 14
13 14 15
(:,:,1) =
12 13 14
13 14 15
14 15 16
(:,:,2) =
13 14 15
14 15 16
15 16 17
(:,:,3) =
14 15 16
15 16 17
16 17 18
>>
But I want to save all 27 values in a single matrix
how it can be done
  1 Comment
Sergey Kasyanov
Sergey Kasyanov on 13 Mar 2021
Hello, all 27 values are stored in 3-d dimensional matrix. If you want the 2-d matrix you should to describe what are you want in detail.

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Accepted Answer

ANKUR KUMAR
ANKUR KUMAR on 15 Mar 2021
3D data can be converted to 2D using reshape. You just need to reshape your matrix based on your requirements.
A1=reshape(M,3,[],1);
Above code yields to 3 X 9 matrix.
A2=reshape(M,[],3,1);
Above code yields to 9 X 3 matrix.
A3=reshape(M,9,[],1);
Above code yields to 9 X 3 matrix.
A4=reshape(M,[],9,1);
Above code yields to 3 X 9 matrix.
A1 and A4 are identical, and A2 and A3 are identical.

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