Hi i need some help here to put this into a matlab

Hi there i need some help please

How can i put these understanding into matlab form

while err<tol %I have other sets of code for this

the main thing is here

i like to put these understanding into a code form, without using a for loop as the while loop is to determine how many loops must it get

h=0.5;

a=0;

xnew=(a+h) %First

h=h/2

xnew2=(a+h a+2*h) %Second

h=h/2

xnew3=(a+h, a+2*h, a+4*h, a+6*h) %FOr every new xnew the element size is increase by multiple by 2 and the general form can be written as (a+h, a+2(n)*h) where n is 0,2,4,6,8

h=h/2

xnew4=(a+h, a+2*h, a+4*h, a+6*h, a+8*h, a+10*h, a+12*h, a+14*h)

h=h/2 %and the same set of code is to run until it satisfied the while loop

Please help and thank you in advance

Answer 1

[KALYAN ACHARJYA]

h=0.5;
a=0;
x=a+h;
i=2;
tol=...?
while err<tol 
x=[x a+i*h];  
h=h/2;
i=i+2;
err=..% Update
end 

[Mark Loui]

Hi there i cant call your codes as well, here are the codes i have used.

delete all;clear all;close all;

a=0;

b=1;

h=b-a;

x=a+(h/2);

i=2;

tol=1e-2;

err=0.1;

while err>tol

x(i)=[x a+i*h];

h=h/2;

i=i+2;

err=err-0.1;

end

Answer 2

[David Hill]

i=0;
while err<tol
 xnew{i+1}=a+[h,h*2*(1:2^i-1)];%index into cell array (much better than different variable names)
 h=h/2;
 i=i+1;
 err;%? not sure what you are doing here
end

[Mark Loui]

Hi there i tried your method, it does not output for the xnew variable,

a=0;

b=1;

h=b-a;

err=0.1;

tol=1e-2;

i=0;

while err < tol

h=h/2;

xnew{i+1}=a+[h,h*2*(1:2^i-1)]

i=i+1;

err=err-0.1;

end

here are the codes that i use for the situation