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finding the index of an array in cell array

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I'm trying to find out if an array is an element of a cell array and return the index, so I did
arr ={[1,2,3],[4,45,6]}
index = find([arr{:}] == [1,2,3])
but it didn't work. How can I solve it?
thanks in advance

Accepted Answer

Fangjun Jiang
Fangjun Jiang on 29 Mar 2021
Edited: Fangjun Jiang on 29 Mar 2021
arr ={[1,2,3],[4,45,6]};
>> index=find(cellfun(@(x) all(x==[1 2 3]),arr))
index =
  1 Comment
Stephen Cobeldick
Stephen Cobeldick on 30 Mar 2021
Simpler and more efficient to use isequal:
arr = {[1,2,3],[4,45,6]};
vec = [1,2,3];
fun = @(a)isequal(vec,a);
idx = cellfun(fun,arr)
idx = 1×2 logical array
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