fopen problem help please

In this part of code
disp(filename)
fid=fopen([filename '.hea']);
disp('debug')
I have error
---WFDB/I0005 ->(its a display filename, i have in WFDB folder files I0005.hea and i0005.mat)
---Error using fopen
---First input must be a file name or a file identifier.
Please, help with fopen) (m2020 mac version)

2 Comments

@Anton Gubrienko: please show the complete error message. This means all of the red text.
I suspect that your filename variable is a cell array instead of a character vector or string scalar

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Answers (1)

Ankriti Sachan
Ankriti Sachan on 20 Apr 2021
As Walter mentioned, I am also guessing that you are providing a folder name instead of a filename as the input to the fopen function. Please verify the same. Also, you can verify if any other file in the same folder is accessible using fopen.
I hope this answers your query.

4 Comments

It is unlikely that a name ending in .hea is a directory name. Not out of the question, but not likely.
Ankriti Sachan
Ankriti Sachan on 20 Apr 2021
Edited: Ankriti Sachan on 20 Apr 2021
Hi Walter, yes, even I believe .hea is not a directory name. However, I read a few resources that indicate that the filenames and the path provided might be incorrect for fopen() here. It might be a possibility that the path provided might be level below to the actual path where the files are located.
It seems like the .dat and .atr files are also read in the same way as the .hea files. Also, there are few comments that talk about reading these files in this post. Maybe those can help.
First input must be a file name or a file identifier
You do not get that message if you accidentally name a directory instead of a file.
mkdir junk_dir_for_test
[fid, msg] = fopen('junk_dir_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of directory worked?\n');
fclose(fid)
end
Warning: failed to open file because: "Is a directory
[fid, msg] = fopen('junk_does_not_exist_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of non-existent file worked?\n');
fclose(fid)
end
Warning: failed to open file because: "No such file or directory
[fid, msg] = fopen({'junk_does_not_exist_for_test'});
Error using fopen
First input must be a file name or a file identifier.
if fid < 0
warning('failed to open file named as cell because: "%s', msg);
else
fprintf('fopen of non-existent named as cell file worked?\n');
fclose(fid)
end
The only case you get the error message being observed is if the parameter passed to fopen() is not a character vector or string scalar.
In the context of
% fid=fopen([filename '.hea']);
then if filename were a cell array of character vectors instead of a character vector, you would get that problem.
Sure, thanks for clarifying. That helps.

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on 15 Apr 2021

Commented:

on 20 Apr 2021

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