Boolean Variables in Matlab

50 views (last 30 days)
Akashdeep Saluja
Akashdeep Saluja on 1 Jul 2013
Hi, I want to have a large 2D nxn array in which I want to store 0 or 1 at each cell, so basically a bit would do for one cell of a matrix. And the array I want to create have high dimensions so space is a constraint. So is there any thing which can provide bit access so that the whole program may run using decent memory.
Thanks
  2 Comments
Walter Roberson
Walter Roberson on 1 Jul 2013
What operations do you need to perform on the array?
Akashdeep Saluja
Akashdeep Saluja on 1 Jul 2013
@Walter: basically I want to use the matrix as a chromosome in Genetic Algorithm, if you are not familiar with Genetic Algorithms, I just need to swap some rows of a matrix with other matrix many times in the algorithm.

Sign in to comment.

Answers (1)

Jonathan Sullivan
Jonathan Sullivan on 1 Jul 2013
Edited: Jonathan Sullivan on 1 Jul 2013
No. MATLAB does not have any native bit sized data types. The best you are going to be able to do is to (without creating your own class) is use logicals, which esentially are bytes (8 bits). Also, do not use cell array if you are concerned about space. Each element in a cell array has a non-neglegable amount of overhead to define the size, shape, and type of the data it stores.
help logical
doc logical
  3 Comments
Akashdeep Saluja
Akashdeep Saluja on 1 Jul 2013
Thanks, I haven't used sparse array, my data is not dense you can say it is sparse and about 80% of the elements in the matrix would be zero, but just want to make sure will it be suitable for use in genetic algorithms in which i need to swap rows of matrix A with rows of matrix B, also the matrix would be symmetric so I will be need to swap columns also. So basically the swap between the matrices would be like a '+' sign where horizontal bar represents swap of rows and vertical bar represents columns..
James Tursa
James Tursa on 1 Jul 2013
Edited: James Tursa on 1 Jul 2013
FYI, doing anything that changes the non-zero locations of a sparse matrix will in all likelihood lead to copying the entire underlying dataset to new memory. I.e., each and every operation you do that changes the non-zero locations will cause an entire dataset copy to take place. This will drag your performance considerably depending on the sizes involved.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!