How to convert cell array to float array?

Hello! I have a cell array (1000x11) of binary digits like that:

0 1 0 0 0 0 1 0 0 0 0

0 1 0 1 1 1 0 1 1 1 0

1 1 1 0 0 1 0 1 1 1 0

0 0 1 1 1 1 1 0 1 1 0

0 0 0 1 0 0 0 0 1 1 1

0 0 0 0 0 1 0 0 0 1 1

...

Each 11 digit row represents a float number, where the last 10 digits are the numbers after the dot. How can I convert that cell array to an array (1000x1) of decimal floats for example :

0.528

0.750

1.814

0.502

0.135

0.035

...

Answer 1

[Jan]

% If the input is a cell containing the chars '0' and '1':
B = cell2mat(YourCell);
Value = B(:, 1) - '0' + bin2dec(B(:, 2:11)) / 1000;

[EDITED] and if the values are the doubles 0 and 1:

B = cell2mat(YourCell);
Value = B(:, 1) + (B(:, 2:11) * 2.^(9:-1:0).') / 1000;

By the way, this would be more efficient for the first case also:

B = cell2mat(YourCell) - '0';
Value = B(:, 1) + (B(:, 2:11) * 2.^(9:-1:0).') / 1000;

[Nick]

I did that but I'm getting an error :

Error using bin2dec (line 36)

Input must be a character vector.

[Jan]

Unfortunately you did not provide some input data, which I could download or use by copy&paste. Therefore my answer contained some guessing about the type of your inputs.

I'm adding a version for numerical values in the input cell, wait some minutes...

Answer 2

[Stephen23]

M = [... as a numeric matrix (e.g. CELL2MAT or STR2DOUBLE)
0	1	0	0	0	0	1	0	0	0	0
0	1	0	1	1	1	0	1	1	1	0
1	1	1	0	0	1	0	1	1	1	0
0	0	1	1	1	1	1	0	1	1	0
0	0	0	1	0	0	0	0	1	1	1
0	0	0	0	0	1	0	0	0	1	1];
V = pow2(9:-1:0)/1000;
D = M(:,1)+M(:,2:end)*V(:)

D = 6×1

0.5280 0.7500 1.8140 0.5020 0.1350 0.0350

Or, depending on how those binary digits are specified:

V = pow2(0:-1:-10);
D = M*V(:)

D = 6×1

0.5156 0.7324 1.7949 0.4902 0.1318 0.0342