How to do operation between number inside two cell

Hi All,

I have two tables, table A and B. Each table consists of three coloumns defining the longitude, latitude and temperature value. The temperature coloum is in cell type.

Then, each of row of cell coloumn consists of different number. Please see the picture.

Is there a way to do '-' (minus) operator between number inside cell in first column of Table A and Table B?

Thank you

[Image Analyst]

Make it easy for us to help you. Please attach the table in a .mat file. I think you'll need to extract the cell array from the table first, then extract the contents of the cell arrays after that. Then do your math. Something like (untested) because you did not attach your data

ca1 = t{1, 1};
ca2 = t{2, 1};
if length(ca1) == length(ca2)
    % Then do something like subtract them
    contents1 = cell2mat(..............)

[Ahmad Bayhaqi]

Hi @Image Analyst

Thank you very much for your response.

Herewith , I attach the mat file of my data. I want to do "daily minus climatolog" for the first coloumn.

However, I havent got the result yet.

your help is greatly appreciated.

Thank you

Answer 1

[Sulaymon Eshkabilov]

Hi,

Here is the simple solution to your exercise:

clc
D1 = load('climatology.mat');
D2=load('daily.mat');
LAT = D1.nu_table4.Lat-D2.new_table4.Lat;  % You can also perform '+'
LON = D1.nu_table4.Lon-D2.new_table4.Lon;  % You can also perform '+'

for jj=1:5
    T1{1, jj} = D1.nu_table4.extdata{ii,1}{jj,1}-D2.new_table4.extData{ii,1}{jj,1}; % You can also perform '+'
end
for jj=1:4
    T2{1, jj} = D1.nu_table4.extdata{ii,1}{jj,1}-D2.new_table4.extData{ii,1}{jj,1}; % U may use'+'
end
for jj=1:4
    T3{1, jj} = D1.nu_table4.extdata{ii,1}{jj,1}-D2.new_table4.extData{ii,1}{jj,1};
end
for jj=1:5
    T4{1, jj} = D1.nu_table4.extdata{ii,1}{jj,1}-D2.new_table4.extData{ii,1}{jj,1};
end
for jj=1:5
    T5{1, jj} = D1.nu_table4.extdata{ii,1}{jj,1}+D2.new_table4.extData{ii,1}{jj,1};
end

Good luck.

[Ahmad Bayhaqi]

Hi @Sulaymon Eshkabilov

Thank you very much.

It works well.

[Sulaymon Eshkabilov]

Most welcome! It is just a pleasure!

[Siddharth Bhutiya]

You could generalize this approach by using cellfun. First of all you can write a small function that would handle the subtraction for each row. So it will iterate over each double vector inside the cell array and subtract them. Then you can simply use cellfun with this function to deal with the entire table.

function out = cell_subtract(a,b)
    assert(isequal(size(a),size(b))); % Make sure both have the same sizes
    out = cell(size(a));
    for i = 1:numel(out)
        assert(isequal(size(a{i}),size(b{i}))); % Internal sizes should match
        % a{i} and b{i} are double vectors so they can be directly subtracted.
        out{i} = a{i} - b{i}; 
    end
end

>> a

a =

  5×3 table

     extdata        Lat       Lon  
    __________    _______    ______

    {5×1 cell}    -12.875    90.625
    {4×1 cell}    -12.875    90.875
    {4×1 cell}    -12.875    91.125
    {5×1 cell}    -12.875    91.375
    {4×1 cell}    -12.875    91.625

>> b

b =

  5×3 table

     extData        Lat       Lon  
    __________    _______    ______

    {5×1 cell}    -12.875    90.625
    {4×1 cell}    -12.875    90.875
    {4×1 cell}    -12.875    91.125
    {5×1 cell}    -12.875    91.375
    {4×1 cell}    -12.875    91.625

>> cellfun(@cell_subtract,a.extdata,b.extData,'UniformOutput',false)

ans =

  5×1 cell array

    {5×1 cell}
    {4×1 cell}
    {4×1 cell}
    {5×1 cell}
    {4×1 cell}