How to load MAt file into 3D matrix

5 views (last 30 days)
I want to load 516 Mat files(240x320)into a 3D Matrix A(240,320,516)
The files are called PVCWARM00071,....,PVCWARM0007516
my code so far:
A = zeros(240,320,516)
nummer=0
>> for i= 1:516
nummer = nummer +1
ext = '.MAT'
naam = 'PVCWARM0007'
file= strcat(naam,num2str(nummer),ext)
A(:,:,i) = load(file)
end
i get the error:Conversion to double from struct is not possible. i already tried to make some adjustments with struct2cell and cell2mat without result.
Can someone help?
Thanks
  2 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 9 Aug 2013
What is the name of your matrix in you mat file?
Maxim De Roeck
Maxim De Roeck on 9 Aug 2013
the 3d matrix is called A, the Mat files are 240x320 arrays without a name

Sign in to comment.

Accepted Answer

Evan
Evan on 9 Aug 2013
Edited: Evan on 9 Aug 2013
The answer can be found in the documentation of the load function:
S = load(FILENAME) loads the variables from a MAT-file into a structure array, or data from an ASCII file into a double-precision array.
Since you already initialize A as a double, the line A(:,:i) = load(file) is attempting to save load's structure output into your 3D matrix.
If you already know the name of your variables as they are saved in your mat file, you can call load without an output argument to put them in the workspace, then save them to your 3D matrix. Again, though, it helps to know or find out the variable names when doing this:
A = zeros(240,320,516);
nummer = 0;
for i = 1:516
nummer = nummer +1
ext = '.MAT';
naam = 'PVCWARM0007';
file = strcat(naam,num2str(nummer),ext);
load(file)
A(:,:,i) = B; %if, for example, the variable's name is B
end
  7 Comments
Maxim De Roeck
Maxim De Roeck on 9 Aug 2013
i fixed it:
for i = 1:516
eval(['load PVCWARM0007',int2str(i),';']);
eval (['A(:,:,i) = PVCWARM0007',int2str(i),';']);
end
thanks anyway!!
Evan
Evan on 9 Aug 2013
Edited: Evan on 9 Aug 2013
The method you're using is not recommended, which is why I suggested using dynamic field references. See Azzi's link for an explanation of why eval should be avoided. You also might find this page helpful.

Sign in to comment.

More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 9 Aug 2013
Edited: Azzi Abdelmalek on 9 Aug 2013
A = zeros(240,320,516)
nummer=0
for i= 1:516
nummer = nummer +1
ext = '.MAT'
naam = 'PVCWARM0007'
file= strcat(naam,num2str(nummer),ext)
variable_name=whos('-file',file);
x=load(file)
A(:,:,i) = x.(variable_name.name)
end
  2 Comments
Maxim De Roeck
Maxim De Roeck on 9 Aug 2013
Edited: Azzi Abdelmalek on 9 Aug 2013
i fixed it:
for i = 1:516
eval(['load PVCWARM0007',int2str(i),';']);
eval (['A(:,:,i) = PVCWARM0007',int2str(i),';']);
end
thanks anyway!!

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!