using fopen, issue with the sequence files are opened
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I am having a problem with fopen. I am opening a sequence of snapshots, however 1001 is being treated as the next in the sequence to 100. So fopen is opening files in the following order:
snapshot_100
snapshot_1001
snapshot_1002
snapshot_1003
...
snapshot_101
snapshot_1010
snapshot_1011
Is there a way to get these to open in the correct sequence? My code is as follows:
files=dir(fullfile(dirname, 'snapshot*'));
for i=1:numfiles
files(i).name=fopen(files(i).name,'r','n');
fseek(files(i).name,264,'bof');
[~,count]= fread(files(i).name,1,'int32');
posdata{i}=fread(files(i).name,[3,N],'*float32','n');
[~,count]= fread(files(i).name,1,'int32');
posdata{i}=posdata{i}';
x{i}=posdata{i}(1:N,1);
y{i}=posdata{i}(1:N,2);
z{i}=posdata{i}(1:N,3);
...
I cannot change the number of digits on the snapshots. Any help would be welcome.
1 Comment
Walter Roberson
on 26 Aug 2013
Note: dir() returns the filenames in the order returned by the operating system. In MS Windows, the operating system returns the files in the order stored on the file system. Some of the file systems use byte-level sorting, but some of the less common MS Windows file systems use other orders (or no particular order.)
In short: you should not rely on the order of names returned by dir()
Accepted Answer
More Answers (2)
Image Analyst
on 26 Aug 2013
Parse the filenames so that you extract the numbers into an integer array, then sort the array and get the indexes
[sortedNumbers, sortIndexes] = sort(numberArray);
% Then apply the same sorting order onto your filename array.
files = files(sortIndexes);
(Note: off the top of my head - not tested.)
Walter Roberson
on 26 Aug 2013
0 votes
There is a FEX contribution to sort filenames that contain embedded numbers.
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