How can I expand a matrix by replacing its elements?

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%mod p multiplication%
p=5;
a=0:p-1;
b=repmat(a,p,1);
s=mod(b.*b',p);
the above code generates the matrix s as
s=[0 0 0 0 0;0 1 2 3 4;0 2 4 1 3;0 3 1 4 2;0 4 3 2 1]
Now i need to expand the matrix s of size 5 by 5 to a matrix of size 5 by 25 by replacing the elements in it as:
0 as 10000,
1 as 01000,
2 as 00100,
3 as 00010,
4 as 00001.
so that the new expanded matrix is:
[10000 10000 10000 10000 10000
10000 01000 00100 00010 00001
10000 00100 00001 01000 00010
10000 00010 01000 00001 00100
10000 00001 00010 00100 01000]
I tried doing it using reshape and re-size of matrix but failed to do it.
Is there any way to expand it?
Thank you.
  1 Comment
Jan
Jan on 27 Aug 2013
Edited: Jan on 27 Aug 2013
The resulting matrix does not look like a 5 by 25 matrix. Do you mean:
[1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0; ...
etc
or:
{'10000', '10000', '10000', '10000', '10000'; ...
?

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Accepted Answer

Jan
Jan on 27 Aug 2013
s = [0 0 0 0 0;0 1 2 3 4;0 2 4 1 3;0 3 1 4 2;0 4 3 2 1]
List = {'10000', '01000', '00100', '00010', '00001'}
Result = List(s + 1);

More Answers (4)

Azzi Abdelmalek
Azzi Abdelmalek on 26 Aug 2013
out=arrayfun(@(x) circshift('10000',[0 x]),s,'un',0)
  1 Comment
Pragathi
Pragathi on 27 Aug 2013
Edited: Azzi Abdelmalek on 27 Aug 2013
The code now gives result for any p.
p=7;
a=0:p-1;
b=repmat(a,p,1);
s=mod(b.*b',p);
out=arrayfun(@(x) circshift('10000',[0 x]),s,'un',0)
Thanks a lot.

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Andrei Bobrov
Andrei Bobrov on 27 Aug 2013
Edited: Andrei Bobrov on 27 Aug 2013
q = num2cell(eye(5),2);
out = cell2mat(q(s+1));
or
p=5;
a=0:p-1;
s = rem(a'*a,p) + 1;
ii = bsxfun(@plus,s,p*a);
jj= ndgrid(a+1);
out = zeros(p,p^2);
out(sub2ind([p,p^2],jj,ii)) = 1;

Osama AlThahab
Osama AlThahab on 26 Aug 2013
Edited: Azzi Abdelmalek on 26 Aug 2013
the matrix for example is still 5*5 matrix, and you can replace the numbers 0,1,2,3,4, by making a program with (if statement) like
%mod p multiplication%
for i=1:5
for j=1:5
if a(i,j)=0
a(i,j)=10000
else if a(i,j)=1
a(i,j)=01000
.
.
.
.
end
end
end
  1 Comment
Jan
Jan on 27 Aug 2013
What do you mean by "a(i,j)=01000"? Leading zeros are not meaningful in Matlab for numbers.

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Azzi Abdelmalek
Azzi Abdelmalek on 26 Aug 2013
p=5;
a=0:p-1;
b=repmat(a,p,1);
s=mod(b.*b',p);
s1=arrayfun(@num2str,s,'un',0)
s1=strrep(s1,'0','x0')
s1=strrep(s1,'1','x1')
s1=strrep(s1,'4','00001');
s1=strrep(s1,'3','00010');
s1=strrep(s1,'2','00100');
s1=strrep(s1,'x1','01000')
s1=strrep(s1,'x0','10000')

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