Finding integers between two vectors

hi

im new in the matlab world

i have 2 vectors A and B size (1xM)
i need to find all the integers betwwen corresponding Columns and store the integers in cell arry

for example:

A= 4.54  5.11  9.58  15.04
B= 1.01  3.2   5.5   16.98

i need to create cell arry X that each column contains all the integers between the numbers in A and B columns (1.01-4.54 the integers 2,3,4 3.2-5.11 the integers 4,5... )

X= 

   2 4 6 16
   3 5 7 
   4   8
       9

how can i do it?

thanks

Answer 1

[John Doe]

A= [4.54 5.11 9.58 15.04];
B= [1.01 3.2 5.5 16.98];

C = sort([A; B]);
C(1,:) = ceil(C(1,:));
C(2,:) = floor(C(2,:));

temp = diff(C) + 1;
D = zeros(max(temp),size(C,2));

for ii = 1:size(C,2)
    D(1:temp(ii),ii) = C(1,ii):C(2,ii);
end

[david]

have a more difficult problem and I would be happy if you help me..

i have 4 Matrices in UV axis :

uv1=[umin; vmin; ones(size(P1U))];% (umin,vmin)

uv2=[umax; vmax; ones(size(P2U))];% (umax,vmax)

uv3=[umin; vmax; ones(size(P3U))];% (umin,vmax)

uv4=[umax; vmin; ones(size(P4U))];% (umax,vmin)

Each column in each matrix contains a coordinate(integers) ..all four matrices containing in each column coordinates that build a block i need to find all the integer coordinates in Each block and arrange them in two matrices one for U and one for V, Each column in U corresponds to the column in V

i added a link for picture: https://www.dropbox.com/s/bdvh6xzmjbyurhf/example.jpg

U=

 1 5 8
 2 6 0
 3 7 0
 4 0 0

V=

 2 5 7
 3 6 0
 4 7 0
 8 0 0

thanks

[the cyclist]

@david, I expect you realize this, since you accepted the answer, but this solution has two features that are different from what you specified in your question:

• It is a numeric array, not a cell array.
• It includes extra zeros.

Maybe that doesn't matter to you, but just in case another person tries to use this solution, it is good to realize.

[the cyclist]

@david, I suggest you ask your second question as a brand-new one, rather than as a comment here. You will get more "traffic" seeing it.

Answer 2

[the cyclist]

Here is a slick one-liner:

arrayfun(@(x,y) (ceil(min([x y])):floor(max([x,y])))',A,B,'UniformOutput',false)

Here is a straightforward way with a loop:

A = [4.54 5.11 9.58 15.04];
B = [1.01 3.2 5.5 16.98];

N = length(A);

X = cell(1,length(A));

for i = 1:N

      hi = floor(max([A(i) B(i)]));
      lo = ceil(min([A(i) B(i)]));

      X{i} = (lo:hi)';

end