IEEE 754 32 bit floating point single precision
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I have a matrix with decimal values.
say:
a=[43 75 23;85 34 78;13 78 23]
i want to convert all the values to 32-bit single precision floating point value IEEE 754 format. Can anybody help me...
or just take a=240;
i want to get "01000011011100000000000000000000"
2 Comments
Walter Roberson
on 7 Sep 2013
Not enough bits there. 32 bits is 4 bytes, but you have given a 3 x 3 matrix.
Deepanshu Chauhan
on 27 Aug 2020
here is a video "https://youtu.be/kSv2bIFS0XU"
Answers (2)
Walter Roberson
on 7 Sep 2013
Edited: Walter Roberson
on 7 Sep 2013
t = uint8(a .');
typecast( t(:), 'single')
and then reshape the result as appropriate.
Be sure to check the byte order against the other possibilities.
2 Comments
Sudharsan
on 7 Sep 2013
Walter Roberson
on 7 Sep 2013
Fixed now. I don't know how the extra comma got in there.
Jan
on 8 Sep 2013
This shows the bit pattern of 240 represented as single precision float:
dec2bin(typecast(single(240), 'uint8'))
1 Comment
Diego Garrido-Mendoza
on 17 Jan 2022
Thanks so much!
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