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Hi, I am writing a code that as follows:

arr(p)=abs(c); %absolute value of c

if(arr(p)<1)

if(arr(p)>0.9)

array(t)=white1;

cor(t)=arr(p); %correlation for c>.95 && c<1

t=t+1;

end

end

maximum=max(cor); %maximum value of cor(t)

Now, I am trying to find the first instance the value of maximum comes in the "arr" Array.

I have tried the following:

1.

for v=1:x

if(maximum==arr(v))

% x=find(arr==maximum);

u=u+1;

if(u==1) %making sure only the first max value is taken

q=value(v); %q is becoming always 0.5,have to fix it

end

end

end

and,

2.

x=find(arr==maximum);

and,

3.

x = find(maximum == arr,'first') ;

In the 1st and 2nd try, when I use fprintf to detect the x, it prints blank, such as,

"x is "

In the 3rd try the following error occurs,

Second argument must be a positive scalar integer.

How can I fix it?

Steven Lord
on 4 Jul 2021

You could use logical indexing.

rng('default')

c = randn(1, 10)

arr = abs(c)

% Overwrite those values in arr that are out of bounds with NaN. I'm using

% wider bounds to show the technique with a small data set.

arr(arr > 1.5) = NaN

arr(arr < 0.5) = NaN

[value, location] = max(arr, [], 'omitnan')

If all you're interested in is the value and not its location in c you could delete the elements of arr that fall out of bounds.

arr2 = abs(c);

arr2(arr2 > 1.5) = [];

arr2(arr2 < 0.5) = []

[value2, location2] = max(arr2)

location2 is not the same as location because arr2 does not have the same number of elements as either arr or c.

jiro
on 4 Jul 2021

Is this what you're looking for?

maximum = 5;

arr = [2 4 3 5 7 3 4];

find(arr == maximum, 1)

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