Problem with mvncdf - returning NaN
2 views (last 30 days)
Show older comments
Hello, I am having some problems when using 'mvncdf'. Consider:
mu = [0.4704 14.5809];
cov = [0.0030 0.0922; 0.0922 2.8597];
xl = [8 0];
xu = [12 4];
Then, mvncdf(xl, xu, mu, cov) returns NaN but I cannot understand why. What is more, the documentation doesn't mention anything relative. And, what is even more strange, mvncdf(xu, mu, cov) - mvncdf(xl, mu, cov) (which is equivalent) returns a double, instead of Nan. Is that due to a bug in mvncdf, or do I miss something important?
0 Comments
Accepted Answer
Paul
on 12 Jul 2021
Edited: Paul
on 12 Jul 2021
The limits of area of integration defined in xl and xu are way, way, out in the tails of the density function, which may be why mvncdf is having an issue.
As I understand mvncdf ...let p(x1,x2) be the joint density. Then mvncdf computes the probability, P, given by:
syms p(x1,x2)
xl = sym('xl',[1 2]);
xu = sym('xu',[1 2]);
P = int(int(p,x1,xl(1),xu(1)),x2,xl(2),xu(2))
First, let's take a look at the pdf as defined by the parameters in the question
mu = [0.4704 14.5809];
cov = [0.0030 0.0922; 0.0922 2.8597];
func(mu,cov);
Now, redraw but with a rectangle showing the area of integration:
xlower = [8 0];
xupper = [12 4];
func(mu,cov,xlower,xupper)
As you can see, the area of integration is way out there. I don't know why mvncdf returns NaN in this case instead of zero, but it probably has something to do with trying to integrate a function with incredibly small values.
Now try with a more reasonable area of integration
xlower = [0.4 13];
xupper = [0.5 15];
func(mu,cov,xlower,xupper);
The probability is:
mvncdf(xlower,xupper,mu,cov)
which seems pretty reasoable.
Also, I don't think that mvncdf(xu, mu, cov) - mvncdf(xl, mu, cov) is equivalent
mvncdf(xupper, mu, cov) - mvncdf(xlower, mu, cov)
because it includes area outside of the red rectangle, particularly the light blue region where x1 > 0.4 and x2 < 13.
function func(mu,cov,xlower,xupper)
x1 = 0.2:.001:.8;
x2 = 10:.001:18;
[X1,X2] = meshgrid(x1,x2);
X = [X1(:) X2(:)];
p = mvnpdf(X,mu,cov);
p = reshape(p,length(x2),length(x1));
figure
pcolor(x1,x2,p),shading interp,colorbar
xlabel('x1'),ylabel('x2')
if nargin == 4
rectangle('Position',[xlower(1) xlower(2) xupper(1)-xlower(1) xupper(2)-xlower(2)],'EdgeColor','r');
axis auto
end
end
9 Comments
adam
on 30 Aug 2022
FWIW, this bug is still present in my current version of MATLAB 2021a:
>> x
x =
0.7551 0.4435 -1.5760
>> mu
mu =
-0.8469 -1.9076 2.3800
>> covar
covar =
0.0052 0.0045 0.0027
0.0045 0.0063 0.0028
0.0027 0.0028 0.0015
>> mvncdf(x,mu,covar)
ans =
NaN
Paul
on 30 Aug 2022
Edited: Paul
on 30 Aug 2022
Fixed in either 2021b or 2022a, it appears, unless the extra digits not shown make a difference. However, I didn't get a notice of such, which I have for other issues that I've reported that have been fixed.
x = [0.7551 0.4435 -1.5760];
mu = [-0.8469 -1.9076 2.3800];
covar = [
0.0052 0.0045 0.0027
0.0045 0.0063 0.0028
0.0027 0.0028 0.0015];
mvncdf(x,mu,covar)
More Answers (0)
See Also
Categories
Find more on Sources in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!