last number is out of matrix range range

Hi guys,

I need your help with this problem please, n1=492;n2=354;% first and last elements of x X=n1:(n2-n1)/(length(x)*1.25):n2; where x=[492 486 483 476 474 474 472 468 466 460 456 456 454 452 444 440 438 432 428 424 420 418 414 411 408 400 388 374 354];

the problem is that the last element of X(X(end)=3.549517241379310e+002) will be a little bit greater than n2= 354 ( the last element of x) is there any way to fix this problem to get (X(end)=n2=x(end))

Answer 1

[Image Analyst]

Can't you just use linspace???

outputArray = linspace(startingValue, endingValue, numberOfElements);

Answer 2

[David Sanchez]

you can round the last element:

n1=492; n2=354; x = ones(20,1); X=n1:(n2-n1)/(length(x)*1.25):n2;

X2 = floor(X);

X2 =

Columns 1 through 9

   492   486   480   475   469   464   458   453   447

Columns 10 through 18

   442   436   431   425   420   414   409   403   398

Columns 19 through 26

   392   387   381   376   370   365   359   354

[Abdulaziz]

Thank you David for your answer. I thought there will be a way to control the step size so that last element of X to be the same as last element of x. I forgot to include the x i am sorry. x=[492 486 483 476 474 474 472 468 466 460 456 456 454 452 444 440 438 432 428 424 420 418 414 411 408 400 388 374 354];

Answer 3

[Abdulaziz]

I found this

X=n1:(n2-n1)/floor(length(x)*1.25):n2

if we put floor into the step we are forcing the step to be integer number and thus the last elements of x and X will be the same