# I need to fix the code by using for loop to plot the relative error E in 2 norm versus n.

3 views (last 30 days)
ebtisam almehmadi on 3 Aug 2021
Answered: Sivani Pentapati on 2 Sep 2021
%%%% Taylor ploynomials pn(x)
x=2:0.01:3;
f = 1./x;
p1=1/2.5;
p2= 1/2.5 -(4/25)*(x-2.5);
p3= 1/2.5 -(4/25)*(x-2.5) + (8/125)*(x-2.5).^2;
p4= 1/2.5 -(4/25)*(x-2.5) + (8/125)*(x-2.5).^2 -(16/625)*(x-2.5).^3;
E1=sqrt((f-p1).^2)/sqrt((f).^2)
E2=sqrt((f-p2).^2)/sqrt((f).^2)
E3=sqrt((f-p3).^2)/sqrt((f).^2)
E4=sqrt((f-p4).^2)/sqrt((f).^2)
n=[1 2 3 4]
E=[ E1 E2 E3 E4];
semilogy(n,E)
ebtisam almehmadi on 3 Aug 2021

Sivani Pentapati on 2 Sep 2021
Please refer to the below code snippet to calculate the l2 norm of error in iterative way. For more information, please refer to for loop in MATLAB documentation.
p(1,:)=1/2.5;
for i=2:4
p(i,:)= p(i-1,:)+ (4/25)*(2/5).^(i-2)*(-1).^(i-1)*(x-2.5).^(i-1);
end
E=sqrt((f-p).^2)/sqrt((f).^2);
n=1:4;
semilogy(n,E);

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