Answer this Newtons Method problem
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James Tursa
on 13 Aug 2021
What have you done so far? What specific problems are you having with your code?
Answers (1)
Wan Ji
on 13 Aug 2021
why not use fsolve or fzero? The following is newton's method
function main
f = @(x) [
sin(x(1)*x(2)) + x(1) - x(2);
x(2)*cos(x(1)*x(2)) + 1;
];
TOL = 1e-3;
err = 1;
x0 = [1;2];
iter = 0;
fprintf('Iteration\tx1\tx2\tf1(x1,x2)\tf2(x1,x2)\n');
while err>TOL
iter = iter + 1;
x1 = x0 - diffmat(f,x0,1e-3)\f(x0) ;
err = norm(x1-x0);
x0 = x1;
fval = f(x1);
fprintf('%d\t%f\t%f\t%f\t%f\t\n', iter, x1(1), x1(2), fval(1), fval(2));
end
end
function m = diffmat(fun, x, h)
f0 = fun(x);
m = zeros(numel(f0), numel(x));
for i = 1:1:numel(x)
x0 = x;
x0(i) = x0(i) + h;
fi = (fun(x0) - f0)/h;
m(:,i) = fi;
end
end
Result printed:
Iteration x1 x2 f1(x1,x2) f2(x1,x2)
1 1.079754 1.945311 -0.002579 0.017148
2 1.086147 1.943707 -0.000034 0.000076
3 1.086187 1.943685 0.000000 -0.000000
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