Answer this Newtons Method problem

3 views (last 30 days)
Yash Singhal
Yash Singhal on 13 Aug 2021
Answered: Wan Ji on 13 Aug 2021
  1 Comment
James Tursa
James Tursa on 13 Aug 2021
What have you done so far? What specific problems are you having with your code?

Sign in to comment.

Answers (1)

Wan Ji
Wan Ji on 13 Aug 2021
why not use fsolve or fzero? The following is newton's method
function main
f = @(x) [
sin(x(1)*x(2)) + x(1) - x(2);
x(2)*cos(x(1)*x(2)) + 1;
];
TOL = 1e-3;
err = 1;
x0 = [1;2];
iter = 0;
fprintf('Iteration\tx1\tx2\tf1(x1,x2)\tf2(x1,x2)\n');
while err>TOL
iter = iter + 1;
x1 = x0 - diffmat(f,x0,1e-3)\f(x0) ;
err = norm(x1-x0);
x0 = x1;
fval = f(x1);
fprintf('%d\t%f\t%f\t%f\t%f\t\n', iter, x1(1), x1(2), fval(1), fval(2));
end
end
function m = diffmat(fun, x, h)
f0 = fun(x);
m = zeros(numel(f0), numel(x));
for i = 1:1:numel(x)
x0 = x;
x0(i) = x0(i) + h;
fi = (fun(x0) - f0)/h;
m(:,i) = fi;
end
end
Result printed:
Iteration x1 x2 f1(x1,x2) f2(x1,x2)
1 1.079754 1.945311 -0.002579 0.017148
2 1.086147 1.943707 -0.000034 0.000076
3 1.086187 1.943685 0.000000 -0.000000

Categories

Find more on Get Started with Optimization Toolbox in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!