return or break in nested loop?

Hi everybody,

I have written the codes below :

for i=1:25
if isempty(in_x)
   return
else
    int = int+1;
    aa = in_x-in_x(1);
    bb = find(aa>((SOP+SPH)*dsr/SL));
    if isempty(bb)
       return
    else
       int = int+1;
       ll = in_x(bb(1):size(in_x,2))-in_x(bb(1));
       bb2 = find(ll>((SOP+SPH)*dsr/SL));
       if isempty(bb2)
          return
       else
          int = int+1;
       end
    end
end  
end

I wanna know why when the first condition satisfies, by the return command it goes to the last "end" which is not the corresponding "end" and it should go to the first "end".

is there any other command which i could use instead of return?

[minoo]

I mean my "for loop" ends when first condition satisfies, but i want to do this for 25 times for 25 different data sets.

Answer 1

[David Young]

If your code is a script (not part of a function definition), then "return" returns control to the keyboard - that is, it is like a jump to the end of the script. So the answer to your first question is: it's doing what it is supposed to do.

The answer to your second question is yes, you could use the "break" command if you want to exit the inner loop. You mention this possibility in your question title.

If your problem is that you want to go to the next case if in_x is empty, then just simplify the code to

for i=1:25
if ~isempty(in_x)
    int = int+1;
     % etc.
end  
end

But note that your code will need to do something to change the value of in_x on each iteration.

[minoo]

thanks for your help. I replaced return command with break but my problem still exist. it just do the "for" loop for one time not for 25 times. can you help me to solve this problem?

[David Young]

See the last part of my answer, which has a suggestion for this.

[minoo]

thanks David for your help.it works well