Complicated Question / String Arrays

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Max Müller
Max Müller on 24 Jul 2014
Commented: dpb on 24 Jul 2014
Hey Guys, i have an array of strings which looks like this:
'J_012(105)' 'J_013(106)' 'J_014(107)' 'J_015(2)' J_016(94)' 'J_017(95)'
But I need it to look like this:
'J_012' 'J_013' 'J_014' 'J_015' 'J_016' 'J_017'
So That the ALWAYS the last 4Strings are deleted/kill. Is this possible ?

Accepted Answer

dpb
dpb on 24 Jul 2014
new= cellfun(@(x) x(1:5),old,'uniformoutput',false);
  2 Comments
Max Müller
Max Müller on 24 Jul 2014
Thanks..both ways wokr
dpb
dpb on 24 Jul 2014
If the pattern isn't fixed length, then regexp is useful; if it is then it's overkill...good to see both

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More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 24 Jul 2014
A={'J_012(105)' 'J_013(106)' 'J_014(107)' 'J_015(2)' 'J_016(94)' 'J_017(95)'}
B=cellfun(@(x) x{1} ,regexp(A,'.+(?=\()','match'),'un',0)

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