select the correct row in a table with a different index in the for loop

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Good mornin,
within a for loop (with an index i ranging from 1 to 1440 with an interval of 5( for i:1:5:1440)) I need to select the correct row of a table (containing 288 rows). The problem is that the index of the for loop does not correspond to the correct row of the table, because for i=5 I have to select row 2 of the table, then for i=10 I have to select row 3 of the table and so on. What can I do?
Thanks

Accepted Answer

HWIK
HWIK on 25 Nov 2021
Edited: HWIK on 25 Nov 2021
Is this what you are looking for?
for i=1:5:1440
j = i==1:5:1440;
end
Where j would be your new index in sequential order.

More Answers (2)

dpb
dpb on 25 Nov 2021
j=1;
for i=1:5:1440
j=j+1;
...
end

Peter Perkins
Peter Perkins on 26 Nov 2021
Giulia, you got an asnwer to your specific question, but it's quite possible that you asked too specific a question, and didn't give enough context. Maybe you don't need to loop at all, consider something like
A2 = A(1:5:1440)
Also, 1440 suggests that you should be using a timetable, so maybe something like
a = tt.A(1:5:1440)
And if you need something every 5 minutes, then perhaps look into using retime.

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R2021b

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