# how to count array of 1 and 0 repeated times

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Keaton Looper on 17 Mar 2022
Commented: Image Analyst on 18 Mar 2022
I am tryig to make a counter that will look at a set of data that consists of ones and zeros and count how many times the number 1 is repeated 10 times consecutively and count that occurence as a 1 and any other occurence of a zero or less than 10 times as a zero.

David Hill on 17 Mar 2022
a=ones(1,10);
b=[];
for k=1:10
b=[b,randi(2,1,20)-1,a];
end
% above just generates binary series
s=num2str(b);
s=s(s~=' ');
count=length(regexp(s,'[1]{10,}'));

Matt J on 17 Mar 2022
Edited: Matt J on 17 Mar 2022
Using,
[~,~,runlengths]=groupLims(groupTrue(data==1),1);
count= nnz(runlengths>=10)
Keaton Looper on 18 Mar 2022
its giving me a count of zero when i know it should not be
Image Analyst on 18 Mar 2022
I gave an example below where I prove it worked. If it doesn't work for your vector, attach your vector in a text or mat file.

Image Analyst on 18 Mar 2022
Edited: Image Analyst on 18 Mar 2022
If you have the Image Processing Toolbox, you can use the built-in bwlabel and do it in one line of code. If m is your matrix:
[~, count] = bwlabel(bwareafilt(logical(m), [10, inf]))
Image Analyst on 18 Mar 2022
Here is an example
m = zeros(1, 1000);
% Make 3 stretches of 10 or more:
m(100:110) = 1;
m(330:380) = 1;
m(560:590) = 1;
[~, count] = bwlabel(bwareafilt(logical(m), [10, inf]))
count = 3