How to build a row vector with a loop?

Hello everyone, I am a beginner to matlab and I need help trying to build a row vector on matlab. I have a variable NL that is changed manually each time, but I need y0 to match in this fashion.

For example, if NL=2, y0= [1 0]. y0 should be the length of NL, but the first element should be a 1.

Here is another example, if NL=4, y0= [1 0 0 0].

I would like to be able to do this with a for loop for an arbitrary value of NL, here is my code so far.

Can anyone help me with this please?

Thank you.

[Torsten]

NL = 8;
y0 = zeros(1,NL);
y0(1) = 1.0;
y0

y0 = 1×8

1 0 0 0 0 0 0 0

[Karen Smith]

thank you!!!

[dpb]

Another way just to illustrate --

NL = 8;
y0 =[1 zeros(1,NL-1)];

You can dream up any number of alternatives...

[Voss]

NL = 8;
y0 = 1;
y0(NL) = 0;

y0

y0 = 1×8

1 0 0 0 0 0 0 0

[dpb]

Yes. Which can also be reversed in sequence of course --

NL = 8;
y0(NL) = 0;
y0(1) = 1;

[Voss]

Yes. Or vectorized --

NL = 8;
y0([1 NL]) = [1 0];

y0

y0 = 1×8

1 0 0 0 0 0 0 0

clear y0
y0([NL 1]) = [0 1];

y0

y0 = 1×8

1 0 0 0 0 0 0 0