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Create square marix of values for a 2 variable function.

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Hello,
I have a two variable function for a given domain i.e. f(x,y) for 0<x<100, 0<y<100 and x and y are discretized I want to form a square matrix where in the columns x remains constant and y varies or vices-versa. I have used the function command to create my function but I am struggling in the next part.
x= 0:0.01:100; y= 0:0.01:100;
function f = f(x,y)
f = cos(x)+sin(y);
end

Accepted Answer

Matt J
Matt J on 3 Jul 2023
x= 0:0.01:100; y=(0:0.01:100)';
f=cos(x)+sin(y)
f = 10001×10001
1.0000 1.0000 0.9998 0.9996 0.9992 0.9988 0.9982 0.9976 0.9968 0.9960 0.9950 0.9940 0.9928 0.9916 0.9902 0.9888 0.9872 0.9856 0.9838 0.9820 0.9801 0.9780 0.9759 0.9737 0.9713 0.9689 0.9664 0.9638 0.9611 0.9582 1.0100 1.0099 1.0098 1.0095 1.0092 1.0088 1.0082 1.0076 1.0068 1.0060 1.0050 1.0040 1.0028 1.0016 1.0002 0.9988 0.9972 0.9956 0.9938 0.9920 0.9901 0.9880 0.9859 0.9837 0.9813 0.9789 0.9764 0.9738 0.9711 0.9682 1.0200 1.0199 1.0198 1.0195 1.0192 1.0187 1.0182 1.0175 1.0168 1.0160 1.0150 1.0140 1.0128 1.0116 1.0102 1.0088 1.0072 1.0056 1.0038 1.0020 1.0001 0.9980 0.9959 0.9937 0.9913 0.9889 0.9864 0.9838 0.9811 0.9782 1.0300 1.0299 1.0298 1.0295 1.0292 1.0287 1.0282 1.0275 1.0268 1.0259 1.0250 1.0240 1.0228 1.0216 1.0202 1.0188 1.0172 1.0156 1.0138 1.0120 1.0101 1.0080 1.0059 1.0037 1.0013 0.9989 0.9964 0.9938 0.9911 0.9882 1.0400 1.0399 1.0398 1.0395 1.0392 1.0387 1.0382 1.0375 1.0368 1.0359 1.0350 1.0339 1.0328 1.0316 1.0302 1.0288 1.0272 1.0256 1.0238 1.0220 1.0201 1.0180 1.0159 1.0137 1.0113 1.0089 1.0064 1.0038 1.0010 0.9982 1.0500 1.0499 1.0498 1.0495 1.0492 1.0487 1.0482 1.0475 1.0468 1.0459 1.0450 1.0439 1.0428 1.0415 1.0402 1.0388 1.0372 1.0356 1.0338 1.0320 1.0300 1.0280 1.0259 1.0236 1.0213 1.0189 1.0164 1.0138 1.0110 1.0082 1.0600 1.0599 1.0598 1.0595 1.0592 1.0587 1.0582 1.0575 1.0568 1.0559 1.0550 1.0539 1.0528 1.0515 1.0502 1.0487 1.0472 1.0455 1.0438 1.0420 1.0400 1.0380 1.0359 1.0336 1.0313 1.0289 1.0264 1.0237 1.0210 1.0182 1.0699 1.0699 1.0697 1.0695 1.0691 1.0687 1.0681 1.0675 1.0667 1.0659 1.0649 1.0639 1.0628 1.0615 1.0602 1.0587 1.0572 1.0555 1.0538 1.0519 1.0500 1.0480 1.0458 1.0436 1.0413 1.0389 1.0363 1.0337 1.0310 1.0282 1.0799 1.0799 1.0797 1.0795 1.0791 1.0787 1.0781 1.0775 1.0767 1.0759 1.0749 1.0739 1.0727 1.0715 1.0701 1.0687 1.0671 1.0655 1.0638 1.0619 1.0600 1.0579 1.0558 1.0536 1.0513 1.0488 1.0463 1.0437 1.0410 1.0382 1.0899 1.0898 1.0897 1.0894 1.0891 1.0886 1.0881 1.0874 1.0867 1.0858 1.0849 1.0838 1.0827 1.0814 1.0801 1.0786 1.0771 1.0755 1.0737 1.0719 1.0699 1.0679 1.0658 1.0635 1.0612 1.0588 1.0563 1.0536 1.0509 1.0481
  3 Comments
Matt J
Matt J on 3 Jul 2023
There is no tilde in the code I posted for you, I don't think...
Torsten
Torsten on 3 Jul 2023
Apostrophe means "transposed". So you "add" an (1xn) and an (nx1) vector in the above code. In MATLAB, by implicit expansion, this gives an (nxn) matrix.
Example:
x = [1 2];
y = [7;4];
x + y
ans = 2×2
8 9 5 6
[1+7 2+7;
1+4 2+4]
ans = 2×2
8 9 5 6

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