find duplicated rows in matlab without for loop
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Hello Friedns,
I have a very large matrix with 2 columns. I need to find the location of duplicated rows (the position of them) . However, I don't want to solve this problem with a for loop because I've tried it before (see the attached code) and it takes a long time. I'm looking for an alternative way to do this. I would be grateful if you could suggest me an idea.
Best,
Mina
x = [File(:,1) File(:,2)];
Grid=unique(x,'rows');
for j=1:length(DD)
idx=find(day_of_year==DD(j));
File2=File(idx,:);
for g=1:length(Grid)
[index1] = (ismember(File2(:,[1 2]),Grid(g,:),'rows'));
idx2=find(index1==1);
Total=[Total;Grid(g,1) Grid(g,2) DD(j) mean(File2(idx2,3)) mean(File2(idx2,4)) mean(File2(idx2,5)) mean(File2(idx2,6))];
end
end
0 Comments
Accepted Answer
Matt J
on 21 Jul 2023
Edited: Matt J
on 21 Jul 2023
[~,I]=unique(x,'rows');
locations=setdiff(1:height(x),I) %locations of duplicate rows
2 Comments
Matt J
on 21 Jul 2023
Edited: Matt J
on 21 Jul 2023
It seems that for each line your code is only finding the position of one of the duplicated lines.
I don't think so. It should return the indices of all rows that have been seen before. As you can see below, the final locations list includes all rows except for 1 and 3, which is where a new row is encountered.
x=[ 1 2;
1 2;
0 4;
1 2;
0 4
0 4];
[~,I]=unique(x,'rows');
locations=setdiff(1:height(x),I) %locations of duplicate rows
More Answers (1)
Walter Roberson
on 21 Jul 2023
Moved: Matt J
on 21 Jul 2023
The third output of unique gives the "group number" for each entry. There are different ways of handling that. one of ways is
[unique_rows, ~, ic] = unique(x,'rows');
appears_in_rows = accumarray(ic, (1:size(x,1)).', [], @(v) {v});
T = table(unique_rows, appears_in_rows);
This would create a table in which the first variable is each unique row, and the second variable is a cell array of row indices that are that unique row. The cell array will always have at least one entry, but might have more.
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