anonymous function with rng call inside

I would like to have a time domain function that uses a random number, but is stable over an interval. The anonymous function below does this, but it is not elegant.

f = @(t) {rng(ceil(t/10)), rand(1)}; % returns new random numbers each decade of t

f(2)

ans =

1×2 cell array

{1×1 struct} {[0.4170]}

The random number in second cell is what I want, but it can only be accessed through another variable. Is there a way in Matlab to simply return the random number without all the indirection?

Thank you for any help you can offer.

[William Buller]

Sometimes you just need to ask the question and then it comes to you!

f = @(t) isstruct(rng(ceil(t/10)))*rand(1);

[Paul]

Are there bounds on t?

[Matt J]

f = @(t) isstruct(rng(ceil(t/10)))*rand(1);

Not a good idea. You are assuming sub-expressions in the function are evaluated left-to-right. That is not reliable.Why does the function have to be anonymous?

[Walter Roberson]

@Matt J

MATLAB has a well-defined order of operations, that mostly guarantees left-to-right operations (as modified by the operation precedences, that leads to oddities like c^a^b ). The main exception is the vaguely-documented linear algebra exceptions where for example a'*b might be specially evaluated rather than being evaluated as (a')*b

[Matt J]

@Walter Roberson The order of operations is left-to-right, but not the order of computation of the operands.

[Walter Roberson]

Evidence?

format long g

e('+left',3)+e('+center',4)+e('+right',2)

+left
+center
+right

ans = 
     9

e('*left',3)*e('*center',4)*e('*right',2)

*left
*center
*right

ans = 
    24

e('.*left',3).*e('.*center',4).*e('.*right',2)

.*left
.*center
.*right

ans = 
    24

e('.^-left',3).^-e('.^-center',4).^-e('.^-right',2)

.^-left
.^-center
.^-right

ans = 
                      6561

e('&&left',3)&&e('&&center',4)&&e('&&right',2)

&&left
&&center
&&right

ans = logical
   1

e('|&left',3)|e('|&center',4)&e('|&right',2)

|&left
|&center
|&right

ans = logical
   1

function v = e(where,v)
   disp(where);
end

Answer 1

[Walter Roberson]

f = @(t) struct('rng', rng(ceil(t/10)), 'r1', rand(1)).r1

f = function_handle with value:
    @(t)struct('rng',rng(ceil(t/10)),'r1',rand(1)).r1

f(2)

ans = 0.4170

[Matt J]

I wouldn't trust this, at least not for posterity. Can we be sure struct() will always generate the fields in left to right order? Can we even be sure both struct fields will be assigned before the .r1 operation is applied?

[Walter Roberson]

Yes, we can be sure that the first field will be calculated before the second field, and we can be sure both struct field will be assigned before that dereferencing. struct is not a special operator, so it is bound by the general rule that operands are evaluated left to right -- first the character vector 'rng' then rng(ceil(t/10)) then the character vector 'r1' then rand(1) . Once those are evaluated, they are pushed on the stack for the call to struct and the call to struct is made. The call to struct returns a structure, and then the . operator dereferences a field of the structure.

The functionality of using dot indexing off of the result of an expression is documented somewhere; unfortunately I do not find the relevant portion of documentation at the moment.

Answer 2

[Matt J]

function y=f(t)

  rng(ceil(t/10)); 
  y=rand(1);

end

Answer 3

[Paul]

t = 2*(rand(1,1000)-0.5)*100;
figure
plot(t,f(t,10),'b.',t,f(t,10),'r.')

function y = f(t,interval)
   tinterval = ceil(t/interval);
   [C,ia,ic] = unique(tinterval);
   yout = rand(size(C));
   y = yout(ic);
end

Answer 4

[Matt J]

rng('default')

T= rand(1,10);

t=1:15;

T(ceil(t/10))

ans =

Columns 1 through 9

0.8147 0.8147 0.8147 0.8147 0.8147 0.8147 0.8147 0.8147 0.8147

Columns 10 through 15

0.8147 0.9058 0.9058 0.9058 0.9058 0.9058

Answer 5

[Steven Lord]

If you can use a "named" function like Matt J's answer that would proably be cleanest.

But if you want to draw numbers from a random number generator with a particular seed value and they must be generated inside an anonymous function, without defining a "named" function, rng is not the right tool for this particular application. Use RandStream.create. This creates a temporary random number generator object from which you can draw numbers without affecting any other rand, randn, randi, etc. call.

f = @(t) rand(RandStream.create('twister', 'seed', t), 1, 2)

f = function_handle with value:
    @(t)rand(RandStream.create('twister','seed',t),1,2)

f(1)

ans = 1×2

0.4170 0.7203

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f(2)

ans = 1×2

0.4360 0.0259

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f(1)

ans = 1×2

0.4170 0.7203

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rng(2, 'twister')
rand(1, 2) % Matches f(2)

ans = 1×2

0.4360 0.0259

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rng(1, 'twister')
f(3) % doesn't affect the global generator [SL fixed typo]

ans = 1×2

0.5508 0.7081

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rand(1, 2) % Matches f(1)

ans = 1×2

0.4170 0.7203

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